Question

我正在尝试读取5个微动开关，并计算出多少个处于活动状态以及哪个处于活动状态。在这方面，我成功了。但是，我还想知道一扇门被打开时被带走了多少（doorstatus == 0表示它已打开）。除了使用while doorstatus == 1 do之外，还有其他方法可以检测门状态的变化吗？例如：一个if then循环，它检测到门的状态从0变为1

我现在的代码（不起作用）：

if global.doorstatus == 1 then -- door closed
    checkMicroswitches() -- checks the microswitches
    calculateFree() -- calculates the amount and place of free microswitches
    global.numberFreeStart = global.numberFree
    global.rfidTakenCheck = 0
end

msg.payload = global.numberFreeStart
msg.topic = "numberFreeStart"
sendTo(4, msg)

while (global.doorstatus == 0) do -- door open, rfidTakenCheck = total taken while door was open
    checkMicroswitches()
    calculateFree()
    global.numberFreeEnd = global.numberFree
    global.rfidTakenCheck = global.numberFreeStart - global.numberFreeEnd
    msg.payload = {}
    msg.payload = global.rfidTakenCheck
    msg.topic = "rfidTakenCheck"
    sendTo(3, msg)
    if global.doorstatus == 1 then
        break
    end
end

程序由于while循环而卡住，所以我想更改它。我不知道如何。

Answer 1

您可以将代码更改为以下内容：

local function doorClosed() -- door closed
    checkMicroswitches() -- checks the microswitches
    calculateFree() -- calculates the amount and place of free microswitches
    global.numberFreeStart = global.numberFree
    global.rfidTakenCheck = 0
end

local function doorOpen() -- door open, rfidTakenCheck = total taken while door was open
    checkMicroswitches()
    calculateFree()
    global.numberFreeEnd = global.numberFree
    global.rfidTakenCheck = global.numberFreeStart - global.numberFreeEnd
    msg.payload = {}
    msg.payload = global.rfidTakenCheck
    msg.topic = "rfidTakenCheck"
    sendTo(3, msg)
end

msg.payload = global.numberFreeStart
msg.topic = "numberFreeStart"
sendTo(4, msg)

while(true) do
    global.doorstatus == updateDoorStatus() -- did not see an update to the status in the code you posted.
    if global.doorstatus == 0 then
        doorOpen()
    else
        doorClosed()
    end
end

我假设您正在寻找无限循环的循环。如果不是这种情况，则可以删除while循环并仅使用其中的代码。

如果然后取决于lua值的变化

1 个答案: