我知道哈希码和等号都需要被覆盖。我尝试了下面的程序,想知道为什么列表设置时不能搜索学生,而仅覆盖等于时不能搜索学生:
import java.util.*;
class Student {
private int id;
private String name;
public Student(int id, String name) {
this.name = name;
this.id = id;
}
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
@Override
public boolean equals(Object obj) {
if (obj == null) return false;
if (!(obj instanceof Student))
return false;
if (obj == this)
return true;
return this.getId() == ((Student) obj).getId();
}
}
public class StudentHashcodeEquals {
public static void main(String[] args) {
Student alex1 = new Student(1, "Alex");
Student alex2 = new Student(1, "Alex");
System.out.println("alex1 hashcode = " + alex1.hashCode());
System.out.println("alex2 hashcode = " + alex2.hashCode());
System.out.println("Checking equality between alex1 and alex2 = " + alex1.equals(alex2));
List<Student> studentsLst = new ArrayList <Student>();
studentsLst.add(alex1);
studentsLst.add(alex2);
System.out.println("Arraylist size = " + studentsLst.size());
System.out.println("Arraylist contains Alex = " + studentsLst.contains(new Student(1, "Alex")));
HashSet <Student> students = new HashSet <Student>();
students.add(alex1);
students.add(alex2);
System.out.println("HashSet size = " + students.size());
System.out.println("HashSet contains Alex = " + students.contains(new Student(1, "Alex")));
}
}
/*
alex1 hashcode = 366712642
alex2 hashcode = 1829164700
Checking equality between alex1 and alex2 = true
Arraylist size = 2
Arraylist contains Alex = true
HashSet size = 2
HashSet contains Alex = false
*/
当将学生插入到列表中时,我假设将其插入2个不同的存储桶中,因为哈希码实现不存在,默认对象哈希码将被插入,并将其存储到2个不同的哈希码中,当搜索另一个对象时,它必须首先通过哈希码找到存储桶,但是哈希码实现不存在,然后列表如何仍然能够识别它,而set则不能?
谢谢!
答案 0 :(得分:0)
列表不使用对象的哈希码。根据它们的类型,它们存储对对象的引用数组。
如果您在列表上调用contains
,它将使用.equals()
遍历列表,以检查对象是否在列表中。