我正在开发具有多选项卡布局的angular 7应用程序。每个选项卡都包含一个组件,可以引用其他嵌套的组件。
当用户选择一个新的/另一个选项卡时,当前选项卡上显示的组件将被破坏(我不只是隐藏它们,而且我遵循了这种模式,因为打开的选项卡可能很多,这似乎是一个更快的解决方案对我来说)。由于加载组件的成本可能很高(可能是从API检索到的大量数据),所以我试图将每个组件状态保持在选项卡容器中(在整个应用程序生命周期中保持活动状态)。
一切都按预期进行,但是我想我已经使用了很多代码来满足自己的需求,我希望一切都可以变得更简单(并且不易出错)。
下面是有关我如何做到的摘录。首先,我创建了一个抽象类,选项卡中的每个组件都应扩展。
export abstract class TabbedComponent implements OnInit, OnDestroy {
abstract get componentName(): string;
tab: LimsTab;
host: TabComponent;
private _componentInitialized = false;
constructor(
private _host: TabComponent,
) {
this.host = _host;
}
get componentInitialized(): boolean {
return this._componentInitialized;
}
ngOnInit(): void {
this.tab = this.host.tab;
this.loadDataContext();
this._componentInitialized = true;
}
ngOnDestroy(): void {
this.saveDataContext();
}
get dataContext() {
return this.tab.dataContext;
}
protected abstract saveDataContext(): void;
protected abstract loadDataContext(): void;
}
loadDataContext
和saveDataContext
在具体组件中实现,并且包含用于保存/检索组件实例值的逻辑。此外,我已经使用_componentInitialized
来了解组件何时调用了其生命周期挂钩OnInit:组件可以从其父那里接收@Input,并且ngOnChanges
在OnInit
之前被触发
以下是具体实现的示例:
@Component({
...
})
export class MyComponent extends TabbedComponent implements OnChanges {
private qualityLotTests: QualityLotTestListItem[];
private _selectedTest: QualityLotTestListItem;
@Input()
selectedQualityLot: string;
@Output()
selectedTest: EventEmitter<QualityLotTestListItem> = new EventEmitter<QualityLotTestListItem>();
constructor(_host: TabComponent, private qualityLotService: QualityLotService) {
super(_host);
}
get componentName(): string {
return 'QualityLotTestListComponent';
}
ngOnChanges(changes: SimpleChanges): void {
if (this.componentInitialized) {
// before calling loadData I need to restore previous data (if any)
// this allow me to undestrand if loaded data filters has changed
// I know I restored it if onInit has executed
// if componentInitialized -> onInit has been executed and input parameters passed from parent are changed
this.loadData();
}
}
protected saveDataContext(): void {
this.dataContext[this.componentName].selectedQualityLot = this.selectedQualityLot;
this.dataContext[this.componentName].state = this.state;
this.dataContext[this.componentName].qualityLotTests = this.qualityLotTests;
this.dataContext[this.componentName].selectedSampleTestIDs
= this.selectedSampleTestIDs;
this.dataContext[this.componentName]._selectedTest = this._selectedTest;
}
protected loadDataContext(): void {
let previouslySelectedQualityLot: string;
if (this.dataContext[this.componentName]) {
previouslySelectedQualityLot = this.dataContext[this.componentName].selectedQualityLot;
this.state = this.dataContext[this.componentName].state || this.state;
this.qualityLotTests = this.dataContext[this.componentName].qualityLotTests;
this._selectedTest = this.dataContext[this.componentName]._selectedTest;
} else {
this.dataContext[this.componentName] = {};
}
this.selectedTest.emit(this._selectedTest);
if (this.qualityLotTests && previouslySelectedQualityLot === this.selectedQualityLot) {
this.dataStateChange(<DataStateChangeEvent>this.state);
} else {
this.loadData();
}
}
loadData(): void {
if (this.selectedQualityLot) {
this.loading = true;
this.qualityLotService
.getQualityLotTests(this.selectedQualityLot)
.subscribe(
qualityLotTests => {
this.qualityLotTests = qualityLotTests;
this.gridData = process(this.qualityLotTests, this.state);
this.loading = false;
},
error => (this.errorMessage = <any>error)
);
} else {
this.qualityLotTests = null;
this.gridData = null;
this.state = {
skip: 0,
take: 10
};
this.selectedSampleTestIDs = [];
this.selectedTest.emit(null);
}
}
public dataStateChange(state: DataStateChangeEvent): void {
this.loading = true;
this.state = state;
this.gridData = process(this.qualityLotTests, this.state);
this.loading = false;
}
}
您认为我如何改进上面的代码?
处加载了我的应用程序的摘录答案 0 :(得分:1)
我们可以看到Plunkr进行澄清吗?
我认为可以利用三种常见的模式来保持状态而无需所有对象继承。
在这里,您将获取数据并将其存储在容器组件中,然后通过@Input()
将其传递给演示组件。您可以在此处销毁演示组件,而不必担心丢失状态。
最好使用路由器导航的概念来显示所需的容器组件,以不仅利用现有实践,而且让用户始终知道它们在应用程序中的位置。
如果您从未使用过,则有一定的学习曲线 Redux模式,您可以将应用程序状态存储在一个地方,使其不可变,并从任何组件中引用它。