Question

所以我需要为毕业项目制作一个完整的登录系统。我已经在mysql上建立了一个数据库，该数据库运行良好。登录名的注册部分有效，但是如果我尝试使用刚才创建的帐户登录，则无效。多数情况下，我的错误消息“密码/电子邮件错误”正确吗？

谢谢！

   <?php
    include("config.php");
    session_start();

    $email =$_POST['email'];
   $password =$_POST['password'];
   if(empty($email))
    {

        exit();

    }else {
      $stmt =mysqli_stmt_init($db);
      $sql = "SELECT * FROM users WHERE email=?;";

      if(!mysqli_stmt_prepare($stmt, $sql))
      {

        echo"No data";
      }else
      {
        mysqli_stmt_bind_param($stmt, "s", $email);
        mysqli_stmt_execute($stmt);
        $result = mysqli_stmt_get_result($stmt);
        if($row = mysqli_fetch_assoc($result))
        {
             $combicheck = password_verify($password,$row['password']);
            if($combicheck == false)
            {

                echo"Password / email is wrong";
                  exit();
            }else if($combicheck == true){
            session_start();
            $_SESSION['password'] = $row['password'];
            header('Location: index.html');
            echo"Logged in";
            }

        }else
        {
          echo"Failed";
        }
      }
    }

Answer 1

<form action="login.php" method="POST">
  <input type="text" name="" /> <br />
  <input type="password" name="" /> <br />
  <input type="submit" name="submit" value="login" />
</form>

在php.ini文件中将display_errors = Off更改为display_errors = On

if method =“ POST” 然后在PHP中使用$ _POST

if method =“ GET” 然后在PHP中使用$ _GET

如果不确定是GET还是POST方法

使用

调试

在您的login.php中

echo "This is Post method";
var_dump($_POST);
echo "This is Get method";
var_dump($_GET);

无法登录（MySQL，PHP）

1 个答案: