我目前正在登录登录页面,但是在插入正确的用户名和密码后,它转到checkLogin.php并说不允许直接执行此文件而不是重定向。我无法找到我在哪里弄错了。
<?php
// checkLogin.php
session_start(); // Start a new session
require('connect.php'); // Holds all of our database connection information
// Get the data passed from the form
$username = $_POST['user'];
$password = $_POST['password'];
$username = stripslashes($username);
$password = stripslashes($password);
$sql = "Select
supplier_id as id,
supplier_lastname as lastname,
supplier_firstname as firstname,
supplier_email as email ,
supplier_phone as phone,
'Supplier' as entity_name
FROM suppliers
WHERE suppliers.supplier_id = '$username' AND suppliers.supplier_pw = '$password'
union all
SELECT
customer_id as id,
customer_lastname as lastname,
customer_firstname as firstname,
customer_email as email,
customer_phone as phone,
'Customer' as entity_name
FROM customers
WHERE customers.customer_id = '$username' AND customers.customer_pw = '$password';
";
$result = mysqli_query($sql) or die ( mysqli_error() );
$count = 0;
$line= mysqli_fetch_assoc($result);
while ($line) {
$count++;
$info = $line[5];
}
if ($count == 1 && $info='Supplier') {
$_SESSION['loggedIn'] = "true";
$_SESSION['username'] = $line['id'];
header("Location: application/view_orders.php");
}
elseif ($count == 1 && $info='Customer') {
$_SESSION['loggedIn'] = "true";
$_SESSION['username'] = $line['id'];
header("Location: application/orderForm.php");
}
else {
$_SESSION['loggedIn'] = "false";
echo "<script type='text/javascript'>alert('Log-In failed! Please check your username or password again.'); window.location.href='http://oncommercetrend.com/'</script>";
}
?>
这是我的表格:
<form class="login active" action="checkLogin.php">
<h3>Login</h3>
<div>
<label>Username:</label>
<input name="user"type="text" />
<span class="error">This is an error</span>
</div>
<div>
<label>Password: <!--<a href="forgot_password.html" rel="forgot_password" class="forgot linkform">Forgot your password?</a>--></label>
<input name="password" type="password" />
<span class="error">This is an error</span>
</div>
<div class="bottom">
<div class="remember"><input type="checkbox" /><span>Keep me logged in</span></div>
<input type="submit" value="Login"></input>
<a href="register.html" rel="register" class="linkform">You don't have an account yet? Register here</a>
<div class="clear"></div>
</div>
</form>
这是数据库连接:
$link = mysqli_connect($db_host,$db_user,$db_pass) or die('Unable to establish a DB connection');
mysqli_select_db($db_database,$link);
答案 0 :(得分:0)
以图形形式向您展示更容易,而不是来回评论。
您的表单没有发布方法。
修改为
<form class="login active" action="checkLogin.php" method="post">
如果省略,表格默认为GET方法。
您应该在所有标题后添加exit;
。
您需要将数据库代码更改为此并更改为您的实际设置/凭据:
$db_host = "yourhost";
$db_user = "user";
$db_pass = "password";
$db_database = "database_name";
$link = mysqli_connect($db_host,$db_user,$db_pass,$db_database)
or die("Error " . mysqli_error($link));
改变这个:
$result = mysqli_query($sql) or die ( mysqli_error() );
到此(首先传递DB连接参数)
$result = mysqli_query($link, $sql) or die ( mysqli_error($link) );