反转自定义python加密算法[出于娱乐目的]

Question

所以不久前，我创建了一个有趣的python程序，将给定的消息加扰。它发送在消息中解密所需的所有信息-但我不确定如何提取该信息。 （基本上不知道我自己的注释代码如何工作） 如果有人可以执行以下任一操作： 1.重新注释显示其工作方式的代码 要么 2.找出一种方法来按照相反的步骤自行解码。

如果您喜欢挑战，我相信这会满足您的需求。 代码在下面。

import random
def create_message(txt):
###### We take the message
    listed_txt = []
    listed_ords = []
    final = []
    #Get the length of the message
    num_txt = len(txt)
    #create a key for the decoder to find from the length of the original 
    message
    key = round(num_txt / 2)
    print(key)
    #turn the message into a list of character codes
    for i in range(num_txt):
        listed_txt.append(str(ord(txt[i])))

    print(listed_txt)
    #turn the key into a character code to be added later
    encode_key = 100 + key
    lenlist = len(listed_txt)
    #caeser cipher shift the letters by the key
    for i in range(lenlist):
        part = listed_txt[i]
        part = int(part)
        part += key
        part = chr(part)
        print(part)
        listed_txt[i] = part
    print(listed_txt)
    #create the noise added dependent on the size of the original text
    for i in range(lenlist * key):
        rand_ord = random.randint(-10,20) + 100
        rand_ord = chr(rand_ord)
        listed_ords.append(rand_ord)
    print(listed_ords)
    #Create a new list adding the real messages seperated by key numbers of 
    noise
    for i in range(lenlist):
        for b in range(key):
            final.append(listed_ords[b * i + b])
        final.append(listed_txt[i])
    print(final)
    lenf = len(final)
    final.insert((lenf - key),chr(encode_key))
    print(final)
    new_message = ''.join(final)
    print(new_message)

create_message(input("Enter Message to be encoded: "))
def decode_message(code):
#find the key
    lencode = len(code)
    codelist = []
    for i in code:
        codelist.append(i)
    keypos = round(lencode)
    firstKey = codelist[lencode]