Question

我有一个promise方法，在其中有if条件。当我嘲笑这个诺言方法。我只能返回一个值。我无法同时满足这两个条件。有人可以帮我吗？

import * as React from 'react';
import myLogs from '../service/myLogs';

export class MyMainComponent extends React.Component {

  constructor(...args) {
    super(...args);
    this.getLogs();
  }

  getLogs() {
    myLogs(5).then((logList) => {
        if(logList.length > 0 ) {
            // need to cover this.
        } else {
            // need to cover this.
        }
    });
  }

  render() { return null; }
}

service / myLogs.js

import axios from 'axios';

const myLogs = (loglength) => {
    return axios.get("url).then((response) =>{return response})
}
export default myLogs

service / 模拟 /myLogs.js

const mockValue = [];
const mockValues = ["1", "2"];

const myLogs = (loglength) => {
// if i return "mockValue" then its covering else part. 
// if i return "mockValues" then its covering if part.
// But i want to cover both. how can i mock to cover both.
    return Promise.resolve(mockValue)
}
export default myLogs

test / MyMainComponent.js

jest.mock(../service/myLogs.js
// some other code..

Answer 1

也许您可以使用参数loglength来创建具有所需长度的数组。

赞：

const mockValue = (length) => Array(length).fill(3)
...
const myLogs = (loglength) => {
    return Promise.resolve(mockValue(loglength))
}
export default myLogs

因此，您可以在此处指定每个测试用例所需的日志数量：）

我想在模拟诺言方法时返回两个不同的响应

1 个答案: