Question

我从youtube上获取（搜索）数据的程序出现错误，并且显示错误AttributeError：'function'对象没有属性'read'我在python3上

import urllib.request
from bs4 import BeautifulSoup
import sys

flag = 0
textToSearch = 'hello world'
query = sys.argv[0].strip("\"").replace(" ","+")
url = "https://www.youtube.com/results?search_query=" + query

response = urllib.request.urlopen
html = response.read()

soup = BeautifulSoup(html,"lxml")
for vid in soup.findAll(attrs={'class':'yt-uix-tile-link'}):
if ('https://www.youtube.com' + vid['href']).startswith("https://www.youtube.com/watch?v="):
    flag = 1
print ('https://www.youtube.com' + vid['href'])
if flag == 0:
    print ("No results found") ```

Answer 1

您是否尝试过使用请求库？

像这样：

import requests
from bs4 import BeautifulSoup
import sys

flag = 0
textToSearch = 'hello world'
query = sys.argv[0].strip("\"").replace(" ","+")
url = "https://www.youtube.com/results?search_query=" + query

response = requests.get(url)
html = response.content

soup = BeautifulSoup(html,"lxml")
for vid in soup.findAll(attrs={'class':'yt-uix-tile-link'}):
    if ('https://www.youtube.com' + vid['href']).startswith("https://www.youtube.com/watch?v="):
        flag = 1
    print ('https://www.youtube.com' + vid['href'])
    if flag == 0:
        print ("No results found")

Answer 2

这里已经犯了错误：

response = urllib.request.urlopen
html = response.read()

您将urllib.request.urlopen放入response变量中，而不是调用该函数的结果。

所以不是

response = urllib.request.urlopen

您应该使用适当的参数来调用它：

response = urllib.request.urlopen( .. parameters come here ... )

AttributeError：“函数”对象没有属性“读取”

2 个答案: