Question

我有一个名为geometry的json对象，geometry密钥存储了称为path的数组，而该路径存储了多维数组

我试图遍历路径，但是循环仅返回第一个索引值

$result = curl_exec($ch);
foreach($JsonData->features as $chunk )
{
    $geo =$chunk->geometry->paths;
    echo $geo;
}

预期结果-将路径值存储到一个变量中。实际结果-仅返回一个值。

数据是...

"geometry": { "paths": [ [ [ -9131174.97888261, 3120622.68129019 ], 
    [ -9131167.41739487, 3120625.21649344 ], 
    [ -9131007.49336538, 3120782.33590721 ], 
    [ -9130998.82313552, 3120791.07506482 ] ] ] }

Answer 1

以下代码应使您重回正轨：

<?php
$json = '{ "paths": [ [ [ -9131174.97888261, 3120622.68129019 ], [ -9131167.41739487, 3120625.21649344 ], [ -9131007.49336538, 3120782.33590721 ], [ -9130998.82313552, 3120791.07506482 ] ] ] }';
$object = json_decode($json);

foreach($object->paths[0] as $path) {
    $geo = $path;
    echo $geo[0];
    echo $geo[1];
}

Answer 2

当您继续覆盖$geo中的值时，您只会得到1个值。您应该构建一个数组（使用[]添加每个值），这将为您提供所有结果。您可能还需要调整访问数据的方式，我已将循环更新为$JsonData->features->geometry->paths[0] ...

$geo = [];
foreach($JsonData->features->geometry->paths[0] as $chunk )
{
    $geo[] =$chunk;
}
print_r($geo);

结果类似于...

Array
(
    [0] => Array
        (
            [0] => -9131174.9788826
            [1] => 3120622.6812902
        )

    [1] => Array
        (
            [0] => -9131167.4173949
            [1] => 3120625.2164934
        )

    [2] => Array
        (
            [0] => -9131007.4933654
            [1] => 3120782.3359072
        )

    [3] => Array
        (
            [0] => -9130998.8231355
            [1] => 3120791.0750648
        )

)

如何检索将响应值存储在php嵌套数组中的json响应对象

2 个答案: