Question

我试图从这个Json中获取一些特定的字段。我已经设法检索第一级中的那些但我需要从数据字段中获取一些。我想获得以下数据字段的数组：

data = [(data artist id, data artist id name, and data rank), (data artist id, data artist id name, and data rank)...]

例如：

data = [(ed61fe981f9143fe82536a0e5e9836f7, Rihanna, 1), (668dfb9383684b79ba603605db21ac51, PSY, 2)..]

知道怎么做吗？

Json在下面：

{
" response": {
"class": "chart",
"data": [
    {
        "artist": {
            "class": "artist",
            "id": "ed61fe981f9143fe82536a0e5e9836f7",
            "musicbrainz": "73e5e69d-3554-40d8-8516-00cb38737a1c",
            "name": "Rihanna"
        },
        "rank": 1,
        "value": 42437.6397
    },
    {
        "artist": {
            "class": "artist",
            "id": "668dfb9383684b79ba603605db21ac51",
            "musicbrainz": "f99b7d67-4e63-4678-aa66-4c6ac0f7d24a",
            "name": "PSY"
        },
        "rank": 2,
        "value": 21562.2685
    },

   … goes up to about 200 items
   ],

     "end_time": 1358553600,
    "id": "396c5b836ce74200b2b5b8ba1df28956",
     "name": "high_flyers_plays_total",
     "next_id": null,
     "now_id": "b857276b34cf488f9a934765c3281af7",
     "period": 86400,
     "previous_id": "cb566393058c4ddfa0b957063fbdc2e3",
     "start_time": 1358467200
     },
   "success": true
  }

这是我的php代码：

<?php


  //Chart json url
  $url = "http://website.com";

   function get_json($url)
   {
      $ch = curl_init();

      //Very short time to get json so long timeout not needed
       $timeout = 5;
       curl_setopt($ch,CURLOPT_URL,$url);
       curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);
       curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,$timeout);
       $data = curl_exec($ch);
       curl_close($ch);
       return $data;
   }


   $json = get_json($url);

   $info = json_decode($json,true);




//Prints the outer variables

   print "This is the end_time for the chart : ";
   print $info["response"]["end_time"]."<br />";

   print "This is the name for the chart : ";
   print $info["response"]["name"]."<br />";

   print "This is the UUID of the chart : ";
   print $info["response"]["id"]."<br />";


   print "This is the period for the chart : ";
   print $info["response"]["period"]."<br />";

   /* gets the json data from the URL */




?>

Answer 1

这个怎么样？

$stuff = json_decode($json, true);

$results = array();

foreach($stuff['response']['data'] as $chunk) {
  $artist = $chunk['artist'];
  $id   = $artist['id'];
  $name = $artist['name'];

  $rank = $chunk['rank'];

  $tuple = array($id, $name, $rank);

  $results[] = $tuple;
}

解析嵌套的JSON以检索嵌套的数组值

1 个答案: