Question

在业余时间处理项目时，我遇到了2个错误

var onChosenFileToOpen = function(theFileEntry) { 

$('.nav-tabs li:nth-child(' + $(".nav-tabs").children().length + ') a').click(); //synchronous function that creates a tab
var checker=setInterval(()=>{
  if(currentiframe.contentWindow && currentiframe.contentWindow.editor){//waits those 2 conditions to be true
    currentiframe.contentWindow.readFileIntoEditor(theFileEntry)//content is loaded to that tab
    clearInterval(checker)
  }

},1)};

但是，Human类是在与我的测试器类相同的目录中的另一个文件中创建的。

人类阶级：

Error:(3, 9) cannot find symbol
  symbol:   class Human
  location: class tester

Error:(3, 25) cannot find symbol
  symbol:   class Human
  location: class tester

测试器类：

public class Human extends Character{

  private boolean excercising;
  private boolean studying;

  public Human(){this(0,0.0,0,0,"<NoName>");} //default Constructor 
                                             //calls non-default 
                                             //constructor <below>

  public Human(int i, double j, int k, int l, String m ){ //non- 
                                   //default constructor, didn't 
                                   //feel like making over 2
    intellect = i;                 //constructors                       
    height = j;
    age = k;
    strength = l;
    name = m;
  }

  public void Exercising(int time){ //In retrospect, this and 
                                    //Studying could have been 
                                    //done in the set methods but
    excercising = true;             // whatever, it's a good way 
to demonstrate class calls.
    for(int t = 0; t < time; t++){
      setStrength();                // Class call with no 
                                    //parameters
    }
    excercising = false;
  }

  public void setStrength(){
    if(excercising){
      strength = strength + 1;     //long increment (can change 
                                  //increment factor to 2, 3, etc.)
    }
  }

  public void Studying(int time){
    studying = true;
    for(int t = 0; t < time; t++){  //standard for-loop
      setIntellect();
    }
    studying = false;
  }

  public void setIntellect(){
    if(studying){
      intellect++;            //super-simple increment only by 1
    }
  }

  public void birthday(){
    age+=1;               //simple increment (can change increment factor to 2, 3, etc.)
    System.out.println("Happy Birthday to " + name + " who is now 
                       "+ age +" years old.");
  }

  public String toString(){
    return "Human " + super.toString();
  }
}

我希望它返回一个字符串，相反，我发现类未找到错误。

在重要的情况下，我正在使用IntelliJ IDEA社区版2019.1。

Answer 1

我认为您不能在对象上执行“ .toString（）”，您应该这样做并使用bob.getName（）而不是bob.toString（）：

公共类人类扩展角色{

 String name;

 public void setName(String name){
     this.name = name;
 }

 public String getName(){
        return name;
 }

 public Human(String name){
        this.setName(name)
 }

}

Java未在同一目录中检测到类文件

1 个答案: