Question

我写了一个代码，这是带有2个输入和打印的简单程序。我添加一些代码来防止该名称和年份正确。当输入的数据正确时，我的程序可以正常工作，但是当输入的数据不相等时，可以重新输入，但是在给变量赋了新单词之后，将打印旧单词：/我使用Python 3.7.3

import re
def name_check(x):
    pattern1=r'[A-Za-z]'
    if re.match(pattern1,x):
        pass
    else:
        print ('This is not your name.')
        give_name()
def year_check(y):
    pattern2=r'(\d)'
    if re.match(pattern2,y):
        pass
    else:
        print ('This is not your year of birth.')
        give_year()
def printing(x,y):
    try:
        print('Hey,',x,',in',int(y)+100,'year you will have 100 years.')
    except:
        print ('An error occured.')
def give_name():
    x=str(input('Enter your name: '))
    name_check(x)
    return x
def give_year():
    y=input('Enter your year of birth: ')
    year_check(y)
    return y
def program():
    x=give_name()
    y=give_year()
    printing(x,y)
program()

Answer 1

问题在于您仅在第一次捕获变量（x和y）。试试这个：

import re

def name_check(x):
    pattern1=r'[A-Za-z]'
    if re.match(pattern1,x):
        return True
    else:
        print ('This is not your name.')
        return False

def year_check(y):
    pattern2=r'(\d)'
    if re.match(pattern2,y):
        return True
    else:
        print ('This is not your year of birth.')
        return False

def printing(x,y):
    print(x,y)
    try:
        print('Hey,',x,',in',int(y)+100,'year you will have 100 years.')
    except:
        print ('An error occured.')

def give_name():
    x=str(input('Enter your name: '))
    while not name_check(x):
        x=str(input('Enter your name: '))
    return x

def give_year():
    y=input('Enter your year of birth: ')
    while not year_check(y):
        y=input('Enter your year of birth: ')
    return y

def program():
    x=give_name()
    y=give_year()
    printing(x,y)

program()

Answer 2

在您的程序中，链函数调用后x和y不变。您应该在return和year_check函数中使用name_check，以使x和y生效：

def name_check(x):
    pattern1=r'[A-Za-z]'
    if re.match(pattern1,x):
        return x
    else:
        print ('This is not your name.')
        return give_name()
def year_check(y):
    pattern2=r'(\d)'
    if re.match(pattern2,y):
        return y
    else:
        print ('This is not your year of birth.')
        return give_year()
def printing(x,y):
    try:
        print('Hey,',x,',in',int(y)+100,'year you will have 100 years.')
    except:
        print ('An error occured.')
def give_name():
    x=str(input('Enter your name: '))
    return name_check(x)
def give_year():
    y=input('Enter your year of birth: ')
    return year_check(y)
def program():
    x=give_name()
    y=give_year()
    printing(x,y)
program()

为什么此代码不起作用以及如何修复？

2 个答案: