我有2个表-table1和table2。
在table2中,基于以下条件,table1有多个记录匹配条件:
c_type,h_level,循环,e_id
仅当存在完全匹配1时,我才希望从RIGHT表中进行记录。如果不是,那么element_nm应该为NULL,因此我在输出中的记录与左表完全相同。
SELECT a.*,
b.element_nm
FROM table1 a
LEFT JOIN table2 b ON
a.c_type = b.c_type
AND a.h_level = b.h_level
AND a.loop = b.loop
AND a.e_id = b.e_id
ORDER BY a.file_name,
a.line_num asc;
答案 0 :(得分:2)
由于这仅是一个值,因此可以在select子句中使用Sub查询。否则,您将在LEFT OUTER JOIN
中使用子查询或使用OUTER APPLY
。
SELECT
t1.*,
(
SELECT MIN(t2.element_nm)
FROM table2 t2
WHERE t2.c_type = t1.c_type
AND t2.h_level = t1.h_level
AND t2.loop = t1.loop
AND t2.e_id = t1.e_id
HAVING COUNT(*) = 1
) AS element_nm
FROM table1 t1
ORDER BY t1.file_name, t1.line_num;
答案 1 :(得分:2)
当您只希望第二张表中的一列时,Thorsten的答案有效。但是,如果您想要多列,则有点麻烦。
或者:
SELECT a.*, b.*
FROM table1 a LEFT JOIN
(SELECT b.*,
COUNT(*) OVER (PARTITION BY b.c_type, b.h_level, b.loop, b.e_id) as cnt
FROM b
) b
ON a.c_type = b.c_type AND
a.h_level = b.h_level AND
a.loop = b.loop AND
a.e_id = b.e_id AND
b.cnt = 1
ORDER BY a.file_name, a.line_num asc;
答案 2 :(得分:0)
您应该使用Row_Number,如下所示:
WITH cte AS (
SELECT ROW_NUMBER() OVER(PARTITION BY a.c_type ,a.h_level,a.loop ,a.e_id ) rnum
,a.c_type ,a.h_level,a.loop ,a.e_id FROM table1 a
LEFT JOIN table2 b ON a.c_type = b.c_type AND a.h_level = b.h_level AND a.loop = b.loop AND a.e_id = b.e_id
)
,cte2 AS (SELECT * FROM cte WHERE rnum = 2)
SELECT a.*,
CASE WHEN cte2.element_nm IS NULL then b.element_nm ELSE NULL END element_nm
FROM table1 a
LEFT JOIN table2 b ON a.c_type = b.c_type AND a.h_level = b.h_level AND a.loop = b.loop AND a.e_id = b.e_id
LEFT JOIN cte2 ON a.c_type = cte2.c_type AND a.h_level = cte2.h_level AND a.loop = cte2.loop AND a.e_id = cte2.e_id