Question

当我运行URL http://127.0.0.1:8000/crud/add/1时，它给我错误add() got an unexpected keyword argument 'id'，有人可以帮助我为什么我收到此错误吗？在这里，我已经添加了我的整个代码，有人可以帮我解决这个问题吗？

urls.py

app_name = 'crud'
urlpatterns = [
    path('',views.index, name='index'),
    path('add/',views.add, name='add'),
    path('add/<int:id>',views.add, name='update'),
]

views.py

from django.shortcuts import render

# Create your views here.


from django.http import HttpResponse, HttpResponseRedirect
from django.template import loader
from .models import Pages
from django.urls import reverse
from django.shortcuts import get_object_or_404, render



def index(request):
    pagelist = Pages.objects.all()
    context = {'pagelist': pagelist}
    return render(request, 'polls/index.html', context)

def add(request):
    if request.POST:
        title = request.POST.get("title")
        permialink = request.POST.get("permialink")
        updated_date = request.POST.get("updated_date")
        bodytext = request.POST.get("bodytext")

        page_data = Pages(title=title,permialink=permialink,updated_date=updated_date,bodytext=bodytext)
        page_data.save()
        return HttpResponseRedirect(reverse('crud:index', args=('')))
    else:
        return render(request,'polls/add.html')

Answer 1

您正在URL中传递参数，但未在View函数中接收该参数。您应该像这样定义添加功能

def add(request, id=None):
    pass
    # rest of code

Answer 2

如果您有方法，例如：

@app.route('/transcript/<int:id>', methods=['GET', 'POST'])
def transcript(employeeId):
  if x == 'NoneType': 
        employee = Employee()        
    else:
        employee = Employee(employeeId)

参数与路由不匹配，例如employeeId不等于，因此我们将参数更改为id

@app.route('/transcript/<int:id>', methods=['GET', 'POST'])
def transcript(id):
  if x == 'NoneType': 
        employee = Employee()        
    else:
        employee = Employee(employeeId)

奇怪的是，我们仍然遇到相同的错误。诀窍是您可能未更改了所有旧的employeeId参数的旧出现：

@app.route('/transcript/<int:id>', methods=['GET', 'POST'])
def transcript(id):
  if x == 'NoneType': 
        employee = Employee()        
    else:
        employee = Employee(id)

获取错误add（）在Django中获得了意外的关键字参数'id'

2 个答案: