Question

我正在尝试使用月份和年份下拉菜单输入日期。我正在使用django片段中的小部件。

关于小部件：将日期输入分为两个框的小部件，分别用于月份和年份， “天”默认为该月的第一天。

这是小部件的代码

import datetime
import re
from six import string_types
from django.forms.widgets import Widget, Select
from django.utils.dates import MONTHS
from django.utils.safestring import mark_safe

__all__ = ('MonthYearWidget',)

RE_DATE = re.compile(r'(\d{4})-(\d\d?)-(\d\d?)$')


class MonthYearWidget(Widget):
    """
    A Widget that splits date input into two <select> boxes for month and year,
    with 'day' defaulting to the first of the month.

    Based on SelectDateWidget, in

    django/trunk/django/forms/extras/widgets.py


    """
    none_value = (0, '---')
    month_field = '%s_month'
    year_field = '%s_year'

    def __init__(self, attrs=None, years=None, required=True):
        # years is an optional list/tuple of years to use in the "year" select box.
        self.attrs = attrs or {}
        self.required = required
        if years:
            self.years = years
        else:
            this_year = datetime.date.today().year
            self.years = range(this_year, this_year+10)

    def render(self, name, value, attrs=None):
        try:
            year_val, month_val = value.year, value.month
        except AttributeError:
            year_val = month_val = None
            if isinstance(value, string_types):
                match = RE_DATE.match(value)
                if match:
                    year_val, month_val, day_val = [int(v) for v in match.groups()]

        output = []

        if 'id' in self.attrs:
            id_ = self.attrs['id']
        else:
            id_ = 'id_%s' % name

        month_choices = list(MONTHS.items())
        if not (self.required and value):
            month_choices.append(self.none_value)
        month_choices.sort()
        local_attrs = self.build_attrs(id=self.month_field % id_)
        s = Select(choices=month_choices)
        select_html = s.render(self.month_field % name, month_val, local_attrs)
        output.append(select_html)

        year_choices = [(i, i) for i in self.years]
        if not (self.required and value):
            year_choices.insert(0, self.none_value)
        local_attrs['id'] = self.year_field % id_
        s = Select(choices=year_choices)
        select_html = s.render(self.year_field % name, year_val, local_attrs)
        output.append(select_html)

        return mark_safe(u'\n'.join(output))

    def id_for_label(self, id_):
        return '%s_month' % id_
    id_for_label = classmethod(id_for_label)

    def value_from_datadict(self, data, files, name):
        y = data.get(self.year_field % name)
        m = data.get(self.month_field % name)
        if y == m == "0":
            return None
        if y and m:
            return '%s-%s-%s' % (y, m, 1)
        return data.get(name, None)

我在浏览器中遇到这个错误

TypeError: build_attrs() got an unexpected keyword argument 'id'

我的python版本是3.7.0，而Django版本是2.0.7

如何摆脱这个错误？

Answer 1

您应该将id值作为字典值传递：

local_attrs = self.build_attrs(attrs, {'id':'self.month_field % id_'})

在Django 1.11中，Widget.build_attrs（）签名已更改，因此它只有两个参数：

Django 1.11 fix #28095

请参阅用户Ruan Steenkamp在此处的stackoverflow问题中解决的类似问题： Update to 1.11: TypeError build_attrs() takes at most 2 arguments (3 given)

build_attrs（）得到了意外的关键字参数'id'

1 个答案: