Question

我有一个特殊的问题。我试图使用 for循环将表产品中的行（共有5条）放入php数组（ $ ro ）中。我的代码成功完成了前2个循环，并确认数组中有5行。但是，放入数组的第二行实际上是表中的第三行，就像我说的那样，在第二个循环之后，我的函数停止获取行。

我测试了打印数组和ID并得到以下结果：

1=>Array ( [sku] => JVC200123 [name] => Acme DISC [price] => 1.00 [type] => disc [value] => 700 ) 
2=>Array ( [sku] => GGWP0008 [name] => Preacher [price] => 24.99 [type] => book [value] => 1 ) 
...345

我想念什么？这是有问题的代码：

protected function get_prod($conn1)
{
    $pluck_type = array();
    $objects = array();
    $call_type = 'SELECT id, type FROM products ORDER BY id';
    $type_res = mysqli_query($conn1, $call_type);
    $index = 0;
    while($row = mysqli_fetch_assoc($type_res)){ 
        $pluck_type[$index] = $row;
        $index++;
    }
    for ($roww = 0; $roww < count($pluck_type); $roww++) {
        $product_type = $pluck_type[$roww]['type'];
        $rowid = $pluck_type[$roww]['id'];
        if($product_type == 'disc')
        {
            $sql = "SELECT p.sku, p.name, p.price, p.type, a.value FROM products AS p INNER JOIN attr_size AS a ON p.id = a.product_id WHERE a.id = '".$rowid."';";
            echo $rowid;
        }
        else if ($product_type == 'book')
        {
            $sql = "SELECT p.sku, p.name, p.price, p.type, a.value FROM products AS p  INNER JOIN attr_weight AS a ON p.id = a.product_id WHERE a.id = '".$rowid."';";
            echo $rowid;
        }
        else if ($product_type == 'furniture')
        {
            $sql = "SELECT p.sku, p.name, p.price, p.type, CONCAT(a.height, 'x', a.width, 'x', a.length) AS value FROM products AS p  INNER JOIN attr_dims AS a ON p.id = a.product_id WHERE a.id = '".$rowid."';";
            echo $rowid;
        }
        $val_res = mysqli_query($conn1, $sql);
        $ro = mysqli_fetch_assoc($val_res);
        print_r($ro);
        $objects[$roww] = $ro; 
    }
    $this->objekt = $objects;
}

Answer 1

您正在测试WHERE子句中的错误列。

WHERE a.id = '".$rowid."';";

应该是

WHERE a.product_id = '".$rowid."';";

或

WHERE p.id = '".$rowid."';";

您可以将所有操作作为一个查询来完成：

SELECT *
FROM (
    SELECT p.id, p.sku, p.name, p.price, p.type, a.value 
    FROM products AS p 
    INNER JOIN attr_size AS a ON p.id = a.product_id
    WHERE p.type = 'disc'
    UNION ALL
    SELECT p.id, p.sku, p.name, p.price, p.type, a.value 
    FROM products AS p  
    INNER JOIN attr_weight AS a ON p.id = a.product_id 
    WHERE p.type = 'book'
    UNION ALL
    SELECT p.id, p.sku, p.name, p.price, p.type, CONCAT(a.height, 'x', a.width, 'x', a.length) AS value 
    FROM products AS p  
    INNER JOIN attr_dims AS a ON p.id = a.product_id 
    WHERE p.type = 'furniture'
) AS x
ORDER BY x.id

PHP for循环在2次循环后停止获取MYSQL表行

1 个答案: