Question

对于一个项目，我试图用PHP做一些事情。它需要for循环并且还包含一个循环。初始循环内的for循环按预期运行。它遍历变量并在$i等于count($tasks)

时停止

然而，当我复制粘贴完全相同的循环时，现在使用$tasklists循环在一次迭代后停止。请注意，当我测试count($tasklists)确实返回示例3时，在循环中，当我回显$i时，它第一次回显0。

以下是包含大量评论的代码。

// First let's break up all the tasklists the project has
$tasklists = explode('&', $data['proj_tasklists']);
// Now lets get all the tasks for each tasklist
for($i = 0; $i < count($tasklists); $i++) {
    // Get list_tasks from the tasklist
    $sql_get = "SELECT * FROM tasklists WHERE list_id='".$tasklists[$i]."'";
    $result_get = mysqli_query($con, $sql_get);

    if($result_get) {
        // Now load in the variable
        while($results = mysqli_fetch_array($result_get)) {
            $data['list_tasks'] = $results['list_tasks'];
        };
        // Now let's break that up
        $tasks = explode('&',$data['list_tasks']);
        // Now reset list_tasks
        $data['list_tasks'] = '';
        // Do something for every task
        for($i = 0; $i < count($tasks); $i++) {
            // And get the info for the set task
            $sql_get = "SELECT * FROM tasks WHERE task_id='".$tasks[$i]."'";
            $result_get = mysqli_query($con, $sql_get);

            if($result_get) {
                // Now load it's task_user in a variable
                while($results = mysqli_fetch_array($result_get)) {
                    $data['task_user'] = $results['task_user'];
                };
                // Check if that is the same as that of the user whom was deleted
                if($data['task_user'] == $data['user_id']) {
                    // If the Id is the same update it to ''
                    $sql_update = "UPDATE tasks SET task_user='' WHERE task_id='".$tasks[$i]."'";

                    if (mysqli_query($con, $sql_update)) {
                        // If that worked then add this to the list of addjusted IDs
                        // First check if the variable is empty or not
                        if($data['adjusted'] == '') {
                            // Add the ID plainly
                            $data['adjusted'] = $tasks[$i];
                        } else {
                            // Otherwise preceed the ID with an &
                            $data['adjusted'] = $data['adjusted'].'&'.$tasks[$i];
                        };
                    } else {
                        // Return an error
                        echo json_encode(array(
                            'status'=>'unsuccesful',
                            'where'=>3
                        ));
                        // Exit the php before it returns an succes state
                        exit();
                    };
                };
                // Now reset task_user
                $data['task_user'] = '';
            } else {
                // Return an error
                echo json_encode(array(
                    'status'=>'unsuccesful',
                    'where'=>2
                ));
                // Exit the php before it returns an succes state
                exit();
            };
        };
    } else {
        // Return an error
        echo json_encode(array(
            'status'=>'unsuccesful',
            'where'=>1
        ));
        // Exit the php before it returns an succes state
        exit();
    };
};

Answer 1

您在两个for循环中使用$ i变量。这会在第一个循环中覆盖$ i。

for ($i = 0; $i < $yourVar1; i++){
//some code    
    for ($a =0; $a < $yourVar2; a++){
    //some code
    }
//some code
}

我刚刚将内循环中的$ i更改为$ a，以便它不会再覆盖它。希望能帮到你

Answer 2

// First let's break up all the tasklists the project has
$tasklists = explode('&', $data['proj_tasklists']);
// Now lets get all the tasks for each tasklist
for($i = 0; $i < count($tasklists); $i++) {
    // Get list_tasks from the tasklist
    $sql_get = "SELECT * FROM tasklists WHERE list_id='".$tasklists[$i]."'";
    $result_get = mysqli_query($con, $sql_get);

    if($result_get) {
        // Now load in the variable
        while($results = mysqli_fetch_array($result_get)) {
            $data['list_tasks'] = $results['list_tasks'];
        };
        // Now let's break that up
        $tasks = explode('&',$data['list_tasks']);
        // Now reset list_tasks
        $data['list_tasks'] = '';
        // Do something for every task
        for($z = 0; $z < count($tasks); $z++) {
            // And get the info for the set task
            $sql_get = "SELECT * FROM tasks WHERE task_id='".$tasks[$i]."'";
            $result_get = mysqli_query($con, $sql_get);

            if($result_get) {
                // Now load it's task_user in a variable
                while($results = mysqli_fetch_array($result_get)) {
                    $data['task_user'] = $results['task_user'];
                };
                // Check if that is the same as that of the user whom was deleted
                if($data['task_user'] == $data['user_id']) {
                    // If the Id is the same update it to ''
                    $sql_update = "UPDATE tasks SET task_user='' WHERE task_id='".$tasks[$i]."'";

                    if (mysqli_query($con, $sql_update)) {
                        // If that worked then add this to the list of addjusted IDs
                        // First check if the variable is empty or not
                        if($data['adjusted'] == '') {
                            // Add the ID plainly
                            $data['adjusted'] = $tasks[$i];
                        } else {
                            // Otherwise preceed the ID with an &
                            $data['adjusted'] = $data['adjusted'].'&'.$tasks[$i];
                        };
                    } else {
                        // Return an error
                        echo json_encode(array(
                            'status'=>'unsuccesful',
                            'where'=>3
                        ));
                        // Exit the php before it returns an succes state
                        exit();
                    };
                };
                // Now reset task_user
                $data['task_user'] = '';
            } else {
                // Return an error
                echo json_encode(array(
                    'status'=>'unsuccesful',
                    'where'=>2
                ));
                // Exit the php before it returns an succes state
                exit();
            };
        };
    } else {
        // Return an error
        echo json_encode(array(
            'status'=>'unsuccesful',
            'where'=>1
        ));
        // Exit the php before it returns an succes state
        exit();
    };
};

覆盖内部for循环中的变量$i。在那里使用不同的变量。

对于这个答案，我使用了$z。

PHP for循环在第一次迭代后停止

2 个答案: