Question

当前，我有一个实现插入排序的程序，然后使用二进制搜索对其进行搜索（一个int数组）。看来我目前有1关错误。

我的插入排序应按降序排列。现在，似乎丢失了最后一个位置中存储的值。

#include <stdio.h>
void insertionSort(int nums[], int size)
{
    int i, key, j;
    for (i = 1; i < size; i++)
    {
        key = nums[i];
        j = i - 1;

        /* Move elements of arr[0..i-1], that are
        greater than key, to one position ahead
        of their current position */
        while (j >= 0 && nums[j] > key)
        {
            nums[j + 1] = nums[j];
            j = j - 1;
        }
        nums[j + 1] = key;
    }
}

int binarySearch(int nums[], int size, int searchVal)
{
    int l = 0, r = size - 1;

    while (l <= r)
    {
        int m = l + (r - l) / 2;

        // Check if x is present at mid
        if (nums[m] == searchVal)
            return m;

        // If x greater, ignore left half
        if (nums[m] < searchVal)
            l = m + 1;

        // If x is smaller, ignore right half
        else
            r = m - 1;
    }

    // if we reach here, then element was
    // not present
    return -1;
}

int main()
{
    int n;
    printf("Enter the number of elements (between 1 and 50) in the array: \n");
    scanf("%d", &n);
    int i, nums[n];
    printf("Enter %d positive integers: \n", n);
    for (i = 0; i < n; i++)
    {
        scanf("%d", &nums[i]);
    }
    int x = 0;
    insertionSort(nums, n);
    printf("Enter a positive integer or -1 to quit: \n");
    scanf("%d", &x);
    do
    {
        int ind = binarySearch(nums, n, x);
        if (ind > 0)
        {
            printf("Found\n");
        }
        else
        {
            printf("Not Found\n");

        }
        printf("Enter a positive integer or -1 to quit: \n");
        scanf("%d", &x);
    } while (x != -1);

    return 0;
}

结果：

Enter the number of elements (between 1 and 50) in the array:
9
Enter 9 positive integers:
7
4
10
49
6
12
32
17
Enter a positive integer or -1 to quit:
4
Not Found
Enter an positive integer -1 or to quit
12
Found
Enter a positive integer or -1 to quit:
5
Not Found
Enter a positive integer or -1 to quit:
49
Found
Enter a positive integer or -1 to quit:
-1

您可以看到，除第一个测试外，所有功能都有效，我在这里测试了数字4。有人知道我为什么要加1吗？

Answer 1

#include <stdio.h>

void insertionSort (int nums[], int size)
{
    int i, key, j;
    for (i = 1; i < size; i++) {
        key = nums[i];
        j = i - 1;

        /* Move elements of arr[0..i-1], that are
           greater than key, to one position ahead
           of their current position */
        while (j >= 0 && nums[j] > key) {
            nums[j + 1] = nums[j];
            j = j - 1;
        }
        nums[j + 1] = key;
    }
}

int binarySearch (int nums[], int size, int searchVal)
{
    int l = 0, r = size - 1;

    while (l <= r) {
        int m = l + (r - l) / 2;

        // Check if x is present at mid
        if (nums[m] == searchVal)
            return m;

        // If x greater, ignore left half
        if (nums[m] < searchVal)
            l = m + 1;

        // If x is smaller, ignore right half
        else
            r = m - 1;
    }

    // if we reach here, then element was
    // not present
    return -1;
}

int main ()
{
    int n;
    printf
        ("Enter the number of elements (between 1 and 50) in the array: \n");
    scanf ("%d", &n);
    int i, nums[n];
    printf ("Enter %d positive integers: \n", n);
    for (i = 0; i < n; i++) {
        scanf ("%d", &nums[i]);
    }
    int x = 0;
    insertionSort (nums, n);
    printf ("Enter a positive integer or -1 to quit: \n");
    scanf ("%d", &x);
    do {
        int ind = binarySearch (nums, n, x);
        if (ind >= 0) {
            printf ("Found\n");
        } else {
            printf ("Not Found\n");

        }
        printf ("Enter a positive integer or -1 to quit: \n");
        scanf ("%d", &x);
    } while (x != -1);

    return 0;
}

试试这个只有一个错误可以解决-if（ind> = 0）

Answer 2

虽然您发现检查UIView导致无法找到索引(ind > 0)的元素，而0提供了解决方案，但让我们看一个简短的测试案例来验证{{ 1}}查找排序数组中的所有元素，而用户不必不断输入信息或将信息重定向到您的程序。

每当您测试算法时，都会提供一个简单的验证框架，该框架无需用户输入即可测试所有元素，数字等。以您的“ 9”数字为例。简单地包括一个初始化的数组并排序然后遍历所有值将验证(ind >= 0)是否按预期执行。（这也将使您免于烦恼）。在整个数组上执行搜索的简短代码可以很简单：

binarySearch()

使用/输出示例

binarySearch()

每个元素现在都列为int main (void) { int nums[] = { 7, 4, 10, 49, 6, 12, 32, 17, 21 }, n = sizeof nums / sizeof *nums; insertionSort (nums, n); for (int i = 0; i < n; i++) printf (" %2d (%s)\n", nums[i], binarySearch (nums, n, nums[i]) >= 0 ? "found" : "not found"); }或$ ./bin/bsearchtest 4 (found) 6 (found) 7 (found) 10 (found) 12 (found) 17 (found) 21 (found) 32 (found) 49 (found)，并且代码自行退出。

C中有缺陷的二进制搜索

2 个答案: