Question

我遇到以下错误 “并非在字符串格式化期间转换了所有参数” 我有以下代码：错误指向代码的这一部分

if num % 2 == 0:

def squareodd(num):
    list = []
    for i in num:
        if i % 2 == 0:
            list.append(i**2)
    return list

squareodd("1,2,3,4,5,6")

预期输出应该是所有奇数的平方

Answer 1

def squareodd(num):
    #lst = () # 'tuple' object has no attribute 'append'
    lst = []
    for i in num:
        # if num % 2 == 0: # you are trying to use the % (modulo) operator on the list instead on item of list 
        if i % 2 == 0:
            lst.append(i**2)
    return lst

print (squareodd([1,2,3,4,5,6]))

Answer 2

您需要用逗号分割字符串，然后将其转换为int对象，然后进行迭代。

例如：

def squareodd(num):
    lst = []
    for i in map(int, num.split(",")):
        if i % 2 == 0:
            lst.append(i**2)
    return lst

print(squareodd("1,2,3,4,5,6"))

Python函数对奇数进行平方

2 个答案: