Question

嗨，我正在尝试制作一个函数，将所有从1到number的数字平方（在代码末尾提供给函数）。我也这样做了，所以我有一个if语句，以便它检查数字是否<1并显示“错误”，但是当我输入0作为输入时，它什么都不做？

def print_squares_to_number(number):
    """takes number and prints a table of all integers and their squares from one to number"""
    for numbers in range(1, number + 1):
        if numbers < 1:
            print("ERROR: number must be at least 1")
        else:
            print(numbers, "*", numbers, "=", numbers*numbers)

print_squares_to_number(0)
print_squares_to_number(5)
print_squares_to_number(3)

Answer 1

您的循环部分从1到input_integer+1进行迭代。因此，如果您给出0或任何负整数，range(1, number+1)会变成一个空的可迭代对象，因此它不会打印任何内容。

尝试一下：

def print_squares_to_number(number):
    """takes number and prints a table of all integers and their squares from one to number"""
    if number < 1:
        print("ERROR: number must be at least 1")
    else:
        for numbers in range(1, number + 1):
            print(numbers, "*", numbers, "=", numbers*numbers)

print_squares_to_number(0)
print_squares_to_number(5)
print_squares_to_number(-1)

输出：

ERROR: number must be at least 1
1 * 1 = 1
2 * 2 = 4
3 * 3 = 9
4 * 4 = 16
5 * 5 = 25
ERROR: number must be at least 1

用于对数字进行平方的功能，不打印数字<1

1 个答案: