Question

Am的user＆user_dealer表具有一对多的关系。请找到下表结构。

用户表

 id email          username   
679 test@test.com   sathis  
679 test@test.com   sathis  
679 test@test.com   sathis  
679 test@test.com   sathis  
679 test@test.com   sathis  
679 test@test.com   sathis  
679 test@test.com   sathis  
679 test@test.com   sathis  
680 test@test.com   ram 
680 test@test.com   ram 
680 test@test.com   ram 
681 test@test.com   Steve   
681 test@test.com   Steve   
681 test@test.com   Steve   
681 test@test.com   Steve   
681 test@test.com   Steve

user_dealer表

    user_id dealer_id
    679     J039
    679     J080
    679     J320
    679     J54L
    679     K31P
    679     L05C
    679     T030
    679     V150
    680     J039
    680     J080
    680     J320
    681     ABC12
    681     CD123
    681     opo123
    681     qw123
    681     ieu12

如果我给出用户名（来自用户表），那么它应该检查代码（来自user_dealer表），同一个Dealer_id应该检查是否为其他user_id（来自user_dealer表）提供了该用户名，并且还应返回该user_ids

例如。

 id    username
679    sathis
680    ram

上表中的

，如果我输入sathis作为输入。我应该得到ram作为输出结果。因为Sathis的Dealer_id也向Ram展示了。

请找到用户的模型类

@Getter
@Setter
@Entity
@Table(name = "users")
@JsonIgnoreProperties(ignoreUnknown = true)
@EqualsAndHashCode(of = {"username"})
@ValidDsdPermissions
@ValidApprovalPrivileges
public class User implements Identifiable<Long>, LazilyLoadable {
  @Id
  @GeneratedValue(strategy = GenerationType.AUTO)
  @JsonProperty("userLink")
  private Long id;

  @NotEmpty(message = "{error.model.user.attribute.username.required}")
  @Column(unique = true, nullable = false)
  private String username;


  @NotEmpty(message = "{error.model.user.attribute.email.required}")
  @Email(message = "{error.model.user.attribute.email.format.invalid}")
  @Column(nullable = false)
  private String email;

  @ElementCollection(fetch = FetchType.LAZY)
  @CollectionTable(name = "user_dealers", joinColumns = @JoinColumn(name = "user_id"))
  @BatchSize(size=20)
  @JsonSerialize(using = DealersSerializer.class)
  @JsonDeserialize(using = DealersDeserializer.class)
  private Set<Dealer> dealers = new HashSet<Dealer>();


  }

请找到经销商的型号类别

@Getter
@Setter
@NoArgsConstructor
@Embeddable
@AllArgsConstructor
@JsonIgnoreProperties(ignoreUnknown = true)
@EqualsAndHashCode
public class Dealer {
  @Column(name = "dealer_id")
  private String dealerId;

  @Column(name = "dsd_id")
  private Long dsdId;
}

我尝试使用简单的SQL查询及其按预期的工作方式。请在下面找到查询。

    select id, username 
    from security_development.users 
    inner join (
      select distinct user_id 
      from security_development.user_dealers 
      inner join  (
        select dealer_id 
        from security_development.user_dealers 
        inner join security_development.users ON security_development.user_dealers.user_id = security_development.users.id
        where  username = 'sathis'
      ) t on t.dealer_id = security_development.user_dealers.dealer_id
    ) t2 on t2.user_id = security_development.users.id

请找到下面的休眠查询，其中未考虑/比较dealer_id（应该进行比较）

"SELECT DISTINCT u FROM User u INNER JOIN u.dealers d, User v INNER JOIN v.dealers e WHERE v.username = :username AND u.role.id in (3,2) AND d.dealerId = e.dealerId"

如何将上述普通sql查询转换为Hibernate查询？

休眠内部联接以一对多关系

0 个答案: