Question

我正在尝试从ansible库存文件创建/ etc / host文件。

可用库存文件如下：

[masters]
k8s-master-a.example.com ansible_ssh_host=10.15.90.2
k8s-master-b.example.com ansible_ssh_host=10.15.90.3
k8s-master-c.example.com ansible_ssh_host=10.15.90.4
[etcd]
k8s-etcd-a.example.com ansible_ssh_host=10.15.91.2
k8s-etcd-b.example.com ansible_ssh_host=10.15.91.3
k8s-etcd-c.example.com ansible_ssh_host=10.15.91.4

以下脚本将帮助使用fqdn条目创建它。

$cat inventory.yaml | grep -v '^\[' | sed 's/ansible_ssh_host=//g' | awk '{ print $2 " " $1}' > /etc/hosts

10.15.90.2 k8s-master-a.example.com  
10.15.90.3 k8s-master-b.example.com  
10.15.90.4 k8s-master-c.example.com  
10.15.91.2 k8s-etcd-a.example.com 
10.15.91.3 k8s-etcd-b.example.com 
10.15.91.4 k8s-etcd-c.example.com

但是我想在/ etc / hosts文件中包含k8s-master- *和k8s-etcd- * aslo。最终结果应如下所示。

10.15.90.2 k8s-master-a.example.com k8s-master-a
10.15.90.3 k8s-master-b.example.com k8s-master-b
10.15.90.4 k8s-master-c.example.com k8s-master-c
10.15.91.2 k8s-etcd-a.example.com k8s-etcd-a
10.15.91.3 k8s-etcd-b.example.com k8s-etcd-b
10.15.91.4 k8s-etcd-c.example.com k8s-etcd-c

Answer 1

您只需要awk。这样就可以了：

cat inventory.yaml 
[masters]
k8s-master-a.example.com ansible_ssh_host=10.15.90.2
k8s-master-b.example.com ansible_ssh_host=10.15.90.3
k8s-master-c.example.com ansible_ssh_host=10.15.90.4
[etcd]
k8s-etcd-a.example.com ansible_ssh_host=10.15.91.2
k8s-etcd-b.example.com ansible_ssh_host=10.15.91.3
k8s-etcd-c.example.com ansible_ssh_host=10.15.91.4

awk -F'[[:space:]=]' '/^[^[]/ {split($1, tokens, /[.]/); print $3, $1, tokens[1]}' inventory.yaml  
10.15.90.2 k8s-master-a.example.com k8s-master-a
10.15.90.3 k8s-master-b.example.com k8s-master-b
10.15.90.4 k8s-master-c.example.com k8s-master-c
10.15.91.2 k8s-etcd-a.example.com k8s-etcd-a
10.15.91.3 k8s-etcd-b.example.com k8s-etcd-b
10.15.91.4 k8s-etcd-c.example.com k8s-etcd-c

Answer 2

AWK解决方案：

awk -F'[ =]' '/^[^\[]/ { if (match($1,/\./)) print($NF " " $1 " " substr($1,0,RSTART-1)); }'

测试：

$ awk -F'[ =]' '/^[^\[]/ { if (match($1,/\./)) print($NF " " $1 " " substr($1,0,RSTART-1)); }' inventory.yaml
10.15.90.2 k8s-master-a.example.com k8s-master-a
10.15.90.3 k8s-master-b.example.com k8s-master-b
10.15.90.4 k8s-master-c.example.com k8s-master-c
10.15.91.2 k8s-etcd-a.example.com k8s-etcd-a
10.15.91.3 k8s-etcd-b.example.com k8s-etcd-b
10.15.91.4 k8s-etcd-c.example.com k8s-etcd-c

Answer 3

如果“ d”文件中的数据，请在gnu awk上尝试：

 def setDistinctElements(self, result):
            elements = []
            for chunk in getattr(result, 'chunks'):
                for pr in getattr(chunk, 'prs'):
                    for seg in getattr(pRaid, 'segs'):
                        elements.append(getattr(seg, 'node_id'))

Answer 4

$ awk -F'[=[:space:]]+' 'split($1,f,/[.]/)>1{print $NF, $1, f[1]}' file
10.15.90.2 k8s-master-a.example.com k8s-master-a
10.15.90.3 k8s-master-b.example.com k8s-master-b
10.15.90.4 k8s-master-c.example.com k8s-master-c
10.15.91.2 k8s-etcd-a.example.com k8s-etcd-a
10.15.91.3 k8s-etcd-b.example.com k8s-etcd-b
10.15.91.4 k8s-etcd-c.example.com k8s-etcd-c

操纵AWK字段变量（$ 1，$ 2，..）并将其添加到行尾

4 个答案: