尝试找到一个SQL查询以查找总和的最大值

Question

罪行表包含有关所犯罪行的信息。我试图获得哪个犯罪季度（1,2,3,4）犯罪数量最多。

SELECT financialquarter_ID, SUM(numberOfOffences) FROM offences WHERE financialquarter_ID = 1;

此查询输出4160

SELECT financialquarter_ID, SUM(numberOfOffences) FROM offences WHERE financialquarter_ID = 2;

此查询输出4227

SELECT financialquarter_ID, SUM(numberOfOffences) FROM offences WHERE financialquarter_ID = 3;

此查询输出4647

SELECT financialquarter_ID, SUM(numberOfOffences) FROM offences WHERE financialquarter_ID = 4;

此查询输出4665

因此，我们可以看到四分之一犯罪率最高。我正在尝试查询以输出此financialquarter_ID的ID（第4章）。

到目前为止，我尝试了以下查询，但均未成功。

select yt.financialquarter_ID, yt.numberOfOffences
From offences yt
where numberOfOffences = 
(select max(numberOfOffences) from offences st where yt.financialquarter_ID = st.financialquarter_ID)
GROUP by numberOfOffences DESC
LIMIT 1 

这是桌子。

Answer 1

使用group by和limit：

SELECT financialquarter_ID, SUM(numberOfOffences)
FROM offences
GROUP BY financialquarter_ID
ORDER BY SUM(numberOfOffences) DESC
LIMIT 1;

注意：如果发生平局，则仅返回一行。

Answer 2

这将起作用：

SELECT financialquarter_ID, SUM(numberOfOffences) FROM offences group by 
financialquarter_ID
having SUM(numberOfOffences)=(SELECT count(*) FROM offences group by 
financialquarter_ID order by 
count(*) desc limit 1
);