Question

我有这个代码，它为我提供了每部电影的销售席位：

SELECT mName, SUM(soldSeats)
FROM movie, show, prog
WHERE movie.movieID = prog.movieID
AND prog.showID = show.showID
GROUP BY mName

问题是要找到销售最多座位的电影，我试图添加它，但只获得没有行：

HAVING SUM(soldseats) = (SELECT MAX(SUM(soldseats)) FROM show
GROUP BY solgteplasser)

有人有建议吗？表格如下：Sum of a activity

Answer 1

Select test.* 
from 
(Select movie.mName, SUM(show.soldSeats) as soldseatsum
FROM movie, show, prog
WHere movie.movieId = prog.movieID
AND prog.showID = show.showID
Group by movie.mName
Order by soldseatsum DESC) test
Where rownum<=1

这样您就可以按SUM顺序排列选择并且只使用Rownum选择第一行这是SUm最高的行。

编辑：如果你的SUM列中有Nulls，请确保在ORder之后添加NULLS LAST，如下所示：

.....
.....
Group by movie.mName
    Order by soldseatsum DESC NULLS LAST) test
    Where rownum<=1

找到分组SUM的MAX

1 个答案: