解决此示例https://bl.ocks.org/mbostock/34f08d5e11952a80609169b7917d4172
我正在寻找为数据点本身添加元素的方法,我已经使用圆圈完成了此操作(然后,将鼠标悬停在显示元数据的位置)。
问题在于,使用笔刷或缩放功能时会有延迟。
如何消除面积重新计算和圆圈位置重新计算之间的延迟?
var svg = d3.select("svg"),
margin = {top: 20, right: 20, bottom: 110, left: 40},
margin2 = {top: 430, right: 20, bottom: 30, left: 40},
width = +svg.attr("width") - margin.left - margin.right,
height = +svg.attr("height") - margin.top - margin.bottom,
height2 = +svg.attr("height") - margin2.top - margin2.bottom;
var parsetimestamp = d3.timeParse("%Y%m%d-%H%M");
var x = d3.scaleTime().range([0, width]),
x2 = d3.scaleTime().range([0, width]),
y = d3.scaleLinear().range([height, 0]),
y2 = d3.scaleLinear().range([height2, 0]);
var xAxis = d3.axisBottom(x),
xAxis2 = d3.axisBottom(x2),
yAxis = d3.axisLeft(y);
var brush = d3.brushX()
.extent([[0, 0], [width, height2]])
.on("brush end", brushed);
var zoom = d3.zoom()
.scaleExtent([1, Infinity])
.translateExtent([[0, 0], [width, height]])
.extent([[0, 0], [width, height]])
.on("zoom", zoomed);
var area = d3.area()
.curve(d3.curveMonotoneX)
.x(function(d) { return x(d.timestamp); })
.y0(height)
.y1(function(d) { return y(d.value); });
var area2 = d3.area()
.curve(d3.curveMonotoneX)
.x(function(d) { return x2(d.timestamp); })
.y0(height2)
.y1(function(d) { return y2(d.value); });
svg.append("defs").append("clipPath")
.attr("id", "clip")
.append("rect")
.attr("width", width)
.attr("height", height);
var focus = svg.append("g")
.attr("class", "focus")
.attr("transform", "translate(" + margin.left + "," + margin.top + ")");
var context = svg.append("g")
.attr("class", "context")
.attr("transform", "translate(" + margin2.left + "," + margin2.top + ")");
d3.json(file).then(function(data) {
data.forEach(function(d) {
d.timestamp = parsetimestamp(d.timestamp);
})
console.log(data)
x.domain(d3.extent(data, function(d) { return d.timestamp; }));
y.domain([0, 1]); // NOTE: this assumes 0-1, like precision/recall/accuracy etc.
x2.domain(x.domain());
y2.domain(y.domain());
focus.append("path")
.datum(data)
.attr("class", "top area")
.attr("d", area);
focus.append("g")
.attr("class", "scatter-points")
.selectAll("circle")
.data(data)
.enter()
.append("circle")
.attr("class", "scatter-point")
.attr("cx", function(d) { return x(d.timestamp); })
.attr("cy", function(d) { return y(d.value); })
.attr("r", 3)
focus.append("g")
.attr("class", "axis axis--x")
.attr("transform", "translate(0," + height + ")")
.call(xAxis);
focus.append("g")
.attr("class", "axis axis--y")
.call(yAxis);
context.append("path")
.datum(data)
.attr("class", "area")
.attr("d", area2);
context.append("g")
.attr("class", "axis axis--x")
.attr("transform", "translate(0," + height2 + ")")
.call(xAxis2);
context.append("g")
.attr("class", "brush")
.call(brush)
.call(brush.move, x.range());
svg.append("rect")
.attr("class", "zoom")
.attr("width", width)
.attr("height", height)
.attr("transform", "translate(" + margin.left + "," + margin.top + ")")
.call(zoom);
});
function brushed() {
if (d3.event.sourceEvent && d3.event.sourceEvent.type === "zoom") return; // ignore brush-by-zoom
var s = d3.event.selection || x2.range();
x.domain(s.map(x2.invert, x2));
focus.select(".area").attr("d", area);
focus.select(".axis--x").call(xAxis);
svg.select(".zoom").call(zoom.transform, d3.zoomIdentity
.scale(width / (s[1] - s[0]))
.translate(-s[0], 0));
}
function zoomed() {
if (d3.event.sourceEvent && d3.event.sourceEvent.type === "brush") return; // ignore zoom-by-brush
var t = d3.event.transform;
x.domain(t.rescaleX(x2).domain());
focus.select(".area").attr("d", area);
focus.select(".axis--x").call(xAxis);
focus.selectAll(".scatter-point").transition()
.attr("cx", function(d) { return x(d.timestamp); });
context.select(".brush").call(brush.move, x.range().map(t.invertX, t));
答案 0 :(得分:0)
事实证明,过渡的默认持续时间为一些有意义的值。
将zoomed()
和brushed()
中的过渡持续时间配置为接近零的值就可以解决此问题。
...
focus.selectAll(".scatter-point").transition()
.duration(10)