我有一对线，我想找到它们彼此之间的相交。我知道我可以执行以下两条操作：
from shapely.geometry import LineString
line1 = LineString([(0,0), (1,0), (1,1)])
line2 = LineString([(0,1), (1,1)])
print(line1.intersection(line2)).
假设我有以下多行字符串，我正在寻找每对之间的交集吗？
MULTILINESTRING ((0 0, 0 20), (20 0, 20 20), (7.49080237694725 11.97316968394073, 5.67208473076472 5.229834926470677), (19.01428612819832 3.12037280884873, 25.96681259449994 4.024633854021577), (14.6398788362281 3.119890406724053, 21.51766222234933 1.803845175041164))