Question

我正在编写一个新的应用程序。

几年前，我曾经使用过python 2.x和wxPython，现在我有了Python 3.7.0和wxPythonPhoenix 4.0.4 msw（alas）。

当我尝试将wx.FileDialog与ShowModal一起使用时，程序将冻结。

我以前没有发现有关此的任何问题。我使用了this之类的wxWiki中的代码（对于MWE来说是简化的）。

import wx

class MyFrame(wx.Frame):
    def __init__(self, parent, ID, title):
        wx.Frame.__init__(self, parent, ID, title, size=(400, 200))
        fileMenu = wx.Menu()
        openItem = fileMenu.Append(-1, "&Open...\tCtrl-O", "Open a new recipe")
        menuBar = wx.MenuBar()
        menuBar.Append(fileMenu, "&File")
        self.SetMenuBar(menuBar)
        self.Bind(wx.EVT_MENU, self.OnOpen, openItem)
    def OnOpen(self, event):
        # otherwise ask the user what new file to open
        with wx.FileDialog(self, "Open XYZ file", wildcard="XYZ files (*.xyz)|*.xyz",
                           style=wx.FD_OPEN | wx.FD_FILE_MUST_EXIST) as fileDialog:

            if fileDialog.ShowModal() == wx.ID_CANCEL:
                return     # the user changed their mind

        #you'll never get here      

app = wx.App()
frame = MyFrame(None, -1, "test")
frame.Show()
app.MainLoop()

我真的不明白，而且代码实际上工作了几次。

Answer 1

我从从wxpython wiki复制的最小工作示例开始。

然后我将其简化为您的最小工作示例。我认为问题可能出在<!DOCTYPE html> <html> <head> <style> [contenteditable=true] { position: relative; } [contenteditable=true]:empty:before { content: attr(placeholder); position: absolute; left: 0; right: 0; top: 4px; margin: auto; } #myDiv { border: 1px dashed #AAA; width: 290px; padding: 5px; text-align: left; height: 16px; } </style> </head> <body> <div id="myDiv" contenteditable="true" placeholder="Enter text here..."></div> </body> </html>的ID的-1值上。

最小的最小工作示例（MWE）：

fileMenu.Append(-1, …

根据您的代码，可以完美（始终）正常工作：

import wx                                                                                                                           

app = wx.App()
with wx.FileDialog(None, "Open XYZ file", wildcard="XYZ files (*.xyz)|*.xyz",
                           style=wx.FD_OPEN | wx.FD_FILE_MUST_EXIST) as fileDialog:

    if fileDialog.ShowModal() == wx.ID_CANCEL:
        print("the user changed their mind")
    else:
        # Proceed loading the file chosen by the user
        pathname = fileDialog.GetPath()
        try:
            with open(pathname, 'r') as file:
                print(file.read())
        except IOError:
            wx.LogError("Cannot open file '%s'." % newfile)

更漂亮，并有一些解释：

import wx                                                                                                                           

class MyFrame(wx.Frame):
    def __init__(self, parent, ID, title):
        wx.Frame.__init__(self, parent, ID, title, size=(400, 200))
        fileMenu = wx.Menu()
        openItem = fileMenu.Append(wx.ID_OPEN, "&Open"," Open a file to edit")
        menuBar = wx.MenuBar()
        menuBar.Append(fileMenu, "&File")
        self.SetMenuBar(menuBar)
        self.Bind(wx.EVT_MENU, self.OnOpen, openItem)
    def OnOpen(self, event):
        # otherwise ask the user what new file to open
        with wx.FileDialog(self, "Open XYZ file", wildcard="XYZ files (*.xyz)|*.xyz",
                           style=wx.FD_OPEN | wx.FD_FILE_MUST_EXIST) as fileDialog:

            if fileDialog.ShowModal() == wx.ID_CANCEL:
                return     # the user changed their mind

            # Proceed loading the file chosen by the user
            pathname = fileDialog.GetPath()
            try:
                with open(pathname, 'r') as file:
                    #self.doLoadDataOrWhatever(file)
                    print(file.read()) # see, it works!
            except IOError:
                wx.LogError("Cannot open file '%s'." % newfile)


app = wx.App()
frame = MyFrame(None, wx.ID_ANY, "test")
frame.Show()
app.MainLoop()

另请参见

文件对话框的更多GUI选项：JFileChooser for Python?

最小的wx.FileDialog示例冻结程序

1 个答案:

最小的最小工作示例（MWE）：

根据您的代码，可以完美（始终）正常工作：

更漂亮，并有一些解释：

另请参见