获取带有孔的numpy数组形状的边界

Question

我正在尝试沿着数组中以1表示的形状的边界获取点的ndarray。我尝试使用scipy.spatial.ConvexHull，但由凸包创建的边界并未解决形状中间的孔（我也需要在孔周围形成边界）。我正在尝试从数组创建这种边界。如何计算形状中的孔？

有色区域是应该从中计算边界点的区域。

import numpy as np
from skimage.measure import label, regionprops
import matplotlib.pyplot as plt
from scipy.spatial import Voronoi, voronoi_plot_2d, ConvexHull


arr = np.array([
    [1,1,1,1,1,1,0,0,0,1,0],
    [1,1,1,1,1,1,0,0,0,1,0],
    [1,1,0,0,0,1,1,1,1,1,0],
    [1,1,0,1,1,1,1,1,0,0,0],
    [1,1,1,1,1,1,0,0,0,0,0],
    [0,1,1,1,1,0,0,0,0,0,0],])

coords = []
for x in range(arr.shape[0]):
    for y in range(arr.shape[1]):
        if arr[x][y] > 0:
            tile = [x,y]
            coords.append(tile)
            # print("tile", tile)
coords = np.array(coords)
# print(coords)

hull = ConvexHull(coords)
plt.plot(coords[:,0], coords[:,1], 'o')
for simplex in hull.simplices:
    plt.plot(coords[simplex, 0], coords[simplex, 1], 'k-')

plt.plot(coords[hull.vertices,0], coords[hull.vertices,1], 'r--', lw=2)
plt.plot(coords[hull.vertices[0],0], coords[hull.vertices[0],1], 'ro')

Answer 1

这有点棘手，但是如果将零与正确的内核（v4或v8）进行卷积，则会得到外部加上边界，因此，如果对内部进行var as_tv = new DeviceParameter() { Key = "testkey", DeviceId = new Guid(), Value = "Armed" }; var asp = new ArmingStatusParameter(); if (DeviceValueTypedParameterConverter.TryConvert<ArmingStatuses>(as_tv, asp)) { // work with asp } var po_tv = new DeviceParameter() { Key = "testkey2", DeviceId = new Guid(), Value = "4/15/2019 17:36" }; var pop = new PoweredOnStatusParameter(); if (DeviceValueTypedParameterConverter.TryConvert<DateTime>(po_tv, pop)) { // work with pop } var v_tv = new DeviceParameter() { Key = "testkey3", DeviceId = new Guid(), Value = "17" }; var vp = new VoltageStatusParameter(); if (DeviceValueTypedParameterConverter.TryConvert<int>(v_tv, vp)) { // work with vp } 类运算你只会得到边境。这是一个示例：

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