如何解决错误“错误的整数值:第1行的列'type_id'的'null'”?

时间:2019-04-14 07:08:57

标签: java mysql jsp servlets

Statement s_add_purchase_wedding= conn.createStatement();
String sql_add_purchase_wedding = "INSERT INTO bidservice(token_id,added_id,purchase_id,service_type,type_id,bid_amount,forward_status,confirmation)VALUES"
        + "('"+url_id+"','"+added_id+"','"+purchase_id+"','"+pur_wed.getTypeWedding()+"',1,'"+pur_wed.getAmount()+"','"+pur_wed.getForwardAdmin()+"'"
        + ",'"+pur_wed.getConfirmation()+"')";

s_add_purchase_wedding.executeUpdate(sql_add_purchase_wedding);

我已经声明了url_idadded_id和`puchase_id并为其分配值。

1 个答案:

答案 0 :(得分:0)

您的错误是在表(+“',1,'”)中插入Integer(1)。插入整数的最好方法是(“',” + 1 +“,”)。

这样的时间怎么样?

String sql_add_purchase_wedding = "INSERT INTO bidservice(token_id, added_id, purchase_id, service_type, type_id, bid_amount, forward_status, confirmation) VALUES ("+
                    "'"+ url_id+"',"+
                    "'"+ added_id+"',"+
                    "'"+ purchase_id+"',"+
                    "'"+ pur_wed.getTypeWedding() +"',"+
                    1 +","+
                    "'"+ pur_wed.getAmount()+"',"+
                    "'"+ pur_wed.getForwardAdmin()+"',"+
                    "'"+ pur_wed.getConfirmation()+"'"+
                ")";

s_add_purchase_wedding.executeUpdate(sql_add_purchase_wedding);