Question

我正在编写一个Django应用程序，它从Bugzilla数据库中提取数据，但我无法获取标记。

class Bugzilla_bugs(models.Model):
    class Meta:
        db_table = 'bugs'

    bug_id = models.IntegerField(primary_key=True)
    ...

flagtypes表，描述了所有不同的标志名称及其含义。

class Bugzilla_flagtypes(models.Model):
    class Meta:
        db_table = 'flagtypes'

    name = models.CharField(max_length=50,unique=True)
    description = models.TextField()
    ...

flags表，它是每个bug的bug_id，type_id和status值的一对多映射。

class Bugzilla_flags(models.Model):
    class Meta:
        db_table = 'flags'

    type_id = models.ForeignKey(Bugzilla_flagtypes,related_name='flagtype',db_column='type_id',to_field='name')
    status = models.CharField(max_length=50)
    bug_id = models.ForeignKey(Bugzilla_bugs,related_name='flaglines',db_column='bug_id',to_field='bug_id')

当我尝试获取特定错误的标志时：

bug = Bugzilla_bugs.objects.using('bugzilla').get(bug_id=12345)
bug.flaglines.get(type_id="UnlocksBranch")

我得到例外：

>>> bug.flaglines.get(type_id__name="UnlocksBranch")
Traceback (most recent call last):
  File "<console>", line 1, in <module>
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/manager.py", line 92, in manager_method
    return getattr(self.get_queryset(), name)(*args, **kwargs)
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/query.py", line 351, in get
    num = len(clone)
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/query.py", line 122, in __len__
    self._fetch_all()
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/query.py", line 966, in _fetch_all
    self._result_cache = list(self.iterator())
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/query.py", line 265, in iterator
    for row in compiler.results_iter():
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/sql/compiler.py", line 700, in results_iter
    for rows in self.execute_sql(MULTI):
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/sql/compiler.py", line 786, in execute_sql
    cursor.execute(sql, params)
  File "/usr/local/lib/python2.7/dist-packages/django/db/backends/utils.py", line 81, in execute
    return super(CursorDebugWrapper, self).execute(sql, params)
  File "/usr/local/lib/python2.7/dist-packages/django/db/backends/utils.py", line 65, in execute
    return self.cursor.execute(sql, params)
  File "/usr/local/lib/python2.7/dist-packages/django/db/backends/mysql/base.py", line 128, in execute
    return self.cursor.execute(query, args)
  File "/usr/lib/python2.7/dist-packages/MySQLdb/cursors.py", line 176, in execute
    if not self._defer_warnings: self._warning_check()
  File "/usr/lib/python2.7/dist-packages/MySQLdb/cursors.py", line 92, in _warning_check
    warn(w[-1], self.Warning, 3)
Warning: Incorrect integer value: 'UnlocksBranch' for column 'type_id' at row 1

我正在尝试使用'get'方法来获取flags表中'status'字段的值。

如果我尝试使用flaglines来查询数字type_id，我会得到DoesNotExist。

>>> bug.flaglines.get(type_id=20)
Traceback (most recent call last):
  File "<console>", line 1, in <module>
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/base.py", line 460, in __repr__
    u = six.text_type(self)
  File "/home/shubbard/django/cpe/dev/cpe/bugzilla/models.py", line 160, in __unicode__
    return unicode(self.type_id)
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/fields/related.py", line 572, in __get__
    rel_obj = qs.get()
  File "/usr/local/lib/python2.7/dist-packages/django/db/models/query.py", line 357, in get
    self.model._meta.object_name)
DoesNotExist: Bugzilla_flagtypes matching query does not exist.

我知道错误已设置该标志。

mysql> select * from flags where bug_id=12345;
+-------+---------+--------+--------+
| id    | type_id | status | bug_id |
+-------+---------+--------+--------+
| 71732 |      29 | +      |  12345 |
| 72538 |      41 | +      |  12345 |
| 72547 |      12 | +      |  12345 |
| 72548 |      31 | ?      |  12345 |
| 72549 |      33 | ?      |  12345 |
| 72550 |      20 | ?      |  12345 |
| 72551 |      36 | ?      |  12345 |
+-------+---------+--------+--------+
7 rows in set (0.01 sec)

我做错了什么？

Answer 1

好的，我现在看到，我认为问题是你的标志模型定义为：

type_id = models.ForeignKey(Bugzilla_flagtypes,related_name='flagtype',db_column='type_id',to_field='name')`

...但是在数据库中，type_id表中的flags列明确包含了flagtype的整数id ...换句话说，您的模型定义没有＆＃39; t匹配数据库模式，您需要从上面的ForeignKey中删除to_field。

然后这应该有效：

bug.flaglines.get(type_id__name="UnlocksBranch")

Django：警告：不正确的整数值：＆＃39; UnlocksBranch＆＃39;对于列＆＃39; type_id＆＃39;在第1行

1 个答案: