Question

我从服务器接收到JSONArray，并使用Jsonobject创建了新的Jsonarry，我想将其发送到另一个活动，当我通过异常从jsonarray获取数据时，我也收到了另一个活动

JSOn数组

{"restaurant_name":[{"restaurantname":"Tikka Mehal","fooditemname":"Chicken Fajita Pizza","fooditemprice":"800"},{"restaurantname":"Saege","fooditemname":"Chicken Fajita Pizza","fooditemprice":"800"}]}

AsynTask类

        JSONObject sending_object = new JSONObject();
        JSONArray sending_array = new JSONArray();

        else
        {
            JSONObject jsonObject = new JSONObject(s);
            JSONArray jsonArray = jsonObject.getJSONArray("restaurant_name");
            for(int i =0;i<jsonArray.length();i++)
            {
                JSONObject jsonObject1 = jsonArray.getJSONObject(i);
                sending_array.put((jsonObject1.getString("restaurantname")));
                sending_array.put(jsonObject1.getString("fooditemname"));
                sending_array.put(jsonObject1.getString("fooditemprice"));
            }

            sending_object.put("restaurant_name",sending_array);
            Intent intent = new Intent(context,RestaurantFoodItemActivity.class);
            intent.putExtra("restaurant_names",sending_object.toString());
            context.startActivity(intent);
        }

第二项活动

ArrayList餐厅；

 Intent bundle = getIntent();
    try {
        JSONObject jsonObject = new JSONObject(bundle.getStringExtra("restaurant_names"));
        JSONArray jsonArray = jsonObject.getJSONArray("restaurant_name");
        for(int i =0;i<jsonArray.length();i++)
        {
            JSONObject jsonObject1 = jsonArray.getJSONObject(i);// there through exception
            String r_name = jsonObject1.getString("restaurantname");
            String f_name = jsonObject1.getString("fooditemname");
            String f_price = jsonObject1.getString("fooditemprice");
            restaurants.add(new Restaurant(r_name,f_name,f_price));
        }

Answer 1

使用Parcelable或Serializable接口。尝试在实现Parcelable的Some Restaurant Object中封装json数据。示例：

public class Person implements Parcelable {

private String firstName;
private String lastName;
private List<Person> konwnPersons;
private List<String> qualifications;



public Person() {
    super();
}

public Person(Parcel parcel) {
    this.firstName = parcel.readString();
    this.lastName = parcel.readString();
    this.qualifications = parcel.readArrayList(null);
    this.konwnPersons = parcel.createTypedArrayList(Person.CREATOR);
}


public String getFirstName() {
    return firstName;
}

public void setFirstName(String firstName) {
    this.firstName = firstName;
}

public String getLastName() {
    return lastName;
}

public void setLastName(String lastName) {
    this.lastName = lastName;
}

 public List<String> getQualification() {
    return qualification;
}
public void setQualifications(List<String> qualifications) {
    this.qualifications = qualifications;
}

public List<Person> getKonwnPersons() {
    return konwnPersons;
}

public void setKonwnPersons(List<Person> konwnPersons) {
    this.konwnPersons = konwnPersons;
}


public static final Creator<Person> CREATOR = new Creator<Person>() {
    @Override
    public Person createFromParcel(Parcel source) {
        return new Person(source);
    }

    @Override
    public Person[] newArray(int size) {
        return new Person[size];
    }
};


@Override
public int describeContents() {
    return 0;
}

@Override
public void writeToParcel(Parcel dest, int flags) {
    dest.writeString(this.firstName);
    dest.writeString(this.lastName);
    dest.writeList(this.qualifications);
    dest.writeTypedList(this.konwnPersons);

}
}

现在发送数据使用此：

Intent secondActivityIntent = new Intent(MainActivity.this,Main2Activity.class);
                Person person = new Person();
                person.setFirstName("Rajnish");
                person.setLastName("Suryavanshi");
secondActivityIntent.putExtra("data",person);
                startActivity(secondActivityIntent);

要获取数据，请使用：

Person person = (Person)getIntent().getParcelableExtra("data");

Answer 2

也许是例外，因为您只是将字符串放在json数组中而不是json对象中，并且在下一个活动中，您尝试从不存在的数组中获取jsonObject，您可以进行以下更改

var array = [
   {user:"Julia", startTime: "2019-04-09T11:22:36"}, 
   {user:"Charles", startTime:"2019-04-10T11:22:36"},
   {user:"Lisa", startTime:"2019-04-10T11:22:36"},
   {user:"Hank", startTime:"2019-04-11T11:22:36"},
   {user:"Hank", startTime:"2019-04-08T11:22:36"},

];

function compare(a, b) {

const startA = new Date(a.startTime).getTime();
const startB = new Date(b.startTime).getTime();
return startB - startA;
}

console.log(array.sort(compare));

如果您在第二个活动中保留相同的代码，则应该可以使用

Answer 3

您为什么不使用HashMap？

例如，在发送意图时：

HashMap<String, String> hashMap = new    HashMap<String, String>();
hashMap.put("key", "value");  
Intent intent =
new Intent(this, MyOtherActivity.class);
intent.putExtra("map", hashMap);          

startActivity(intent);

然后在接收活动中：

HashMap<String, String> 
hashMap = (HashMap<String, String>)intent.getSerializableExtra("map");

修改

阅读您的评论后，我认为最好的方法是使用数据库并在获取信息后存储您的信息，然后在第二次活动中使用它们

如何将带有JSONObject对象的JSONArray数组从一个活动发送到第二个活动

3 个答案: