JSONObject data = response.getJSONObject("data");
Iterator x = data.keys();
JSONArray jsonArray = new JSONArray();
while (x.hasNext()){
String key = (String) x.next();
jsonArray.put(data.get(key));
}
Log.d("TZX", String.valueOf(jsonArray));
我对像这样的可变数据有JSONObject
{"type":"DISKON","result":"DUPE","data":{"1":{"Code":"DISC2","Description":"DISC SALES","Value":0},"2":{"Code":"DISC1.5%","Description":"DISC1.5%","Value":1.5},"3":{"Code":"DISC 2%","Description":"DISC 2%","Value":2}}}
如何在JSONObject上获取对象“值”以便在变量“jsonArray”上发送到JSONArray
抱歉我的语法,我是新手 谢谢
答案 0 :(得分:2)
试试这个,
<?php
namespace App\Http\Requests;
class MyRequest extends Request
{
/**
* Determine if the user is authorized to make this request.
*
* @return bool
*/
public function authorize()
{
return true;
}
/**
* Get the validation rules that apply to the request.
*
* @return array
*/
public function rules()
{
return [
'first_field' => 'min:0',
'second_field' => 'min:'.$this->first_field,
];
}
}
答案 1 :(得分:0)
您正在使用数组,因此请直接使用JsonArray
来解析数据,如
JSONArray array = response.getJSONArray("data");
List<Integer> values = new ArrayList<>();
for(int i=0;i < array.length();i++){
values.add(array.getJSONObject(i).getInt("Value"));
}
答案 2 :(得分:0)
你变量puts a[0].object_id # 47369457807480
puts a[1].object_id # 47369457807320
puts a[2].object_id # 47369457807200
puts b[0].object_id # 47369457807070
puts b[1].object_id # 47369457807070
puts b[2].object_id # 47369457807070
不是JSONObject它的JSONArray。
data
从数组
获取JSONObjectdata = [{"Code":"DISC2","Description":"DISC SALES","Value":0},{"Code":"DISC1.5%","Description":"DISC1.5%","Value":1.5},{"Code":"DISC 2%","Description":"DISC 2%","Value":2}]