Question

鉴于此ERD，我试图找出为什么未在documentChildren和documentAttribute上创建外键的原因，因为它们各自都有一列，该列应为document的FK

我的续集模型都运行良好，但是我很好奇我在做错什么，因为没有生成真正的FK。

文档迁移：

'use strict'
module.exports = {
  up: (queryInterface, Sequelize) => {
    return queryInterface.createTable('documents', {
      id: {
        allowNull: false,
        primaryKey: true,
        type: Sequelize.UUID,
        defaultValue: Sequelize.UUIDV4
      },
      ...
    })
  }
  ...
}

documentChildren迁移：

'use strict'
module.exports = {
  up: (queryInterface, Sequelize) => {
    return queryInterface.createTable('documentChildren', {
      id: {
        allowNull: false,
        primaryKey: true,
        type: Sequelize.UUID,
        defaultValue: Sequelize.UUIDV4
      },
      documentId: {
        allowNull: false,
        type: Sequelize.UUID,
        references: {
          model: 'documents',
          key: 'id'
        }
      },
      ...
    })
  }
  ...
}

documentAttribute迁移：

'use strict'
module.exports = {
  up: (queryInterface, Sequelize) => {
    return queryInterface.createTable('documentAttributes', {
      id: {
        allowNull: false,
        primaryKey: true,
        type: Sequelize.UUID,
        defaultValue: Sequelize.UUIDV4
      },
      documentId: {
        allowNull: false,
        type: Sequelize.UUID,
        references: {
          model: 'documents',
          key: 'id'
        }
      },
      ...
    })
  }
  ...
}

文档模型关联：

document.associate = function (models) {
    document.hasMany(models.documentAttribute)
    document.hasMany(models.documentChildren)
  }

Answer 1

您的代码显示

def normalize(val):
    if val < 100:
        return 1
    elif val > 100 and val < 350:
        return 2
    else:
        return 3

df['NO2'] = df['NO2'].apply(normalize)

"documentId" uuid NOT NULL REFERENCES documents(id)是FK。选中postgresql-docs

您对索引的创建感到困惑，但这并不意味着拥有FK。

不会按预期在数据库上创建外键

1 个答案: