可以将两个外键定义为模型的复合主键吗?
用户只能是一个家庭的成员,一个家庭可以有许多成员,而家庭成员表需要用户和家庭的参考
const User = sequelize.define(
'User',
{
id: { type: dataTypes.INTEGER.UNSIGNED, autoIncrement: true, primaryKey: true },
name: { type: dataTypes.STRING(30) },
email: { type: dataTypes.STRING(30) }
...
},
{
classMethods: {
associate(models) {
User.hasOne(models.FamilyMember, {
foreignKey: 'user_id'
}
}
}
}
)
const Family = sequelize.define(
'Family',
{
name: { type: dataTypes.STRING(30) }
},
{
classMethods: {
associate(models) {
Family.hasMany(models.FamilyMember, {
foreignKey: 'family_id'
}
}
}
}
)
const FamilyMember = sequelize.define(
'FamilyMember',
{
name: { type: dataTypes.STRING(30) },
/*
family_id and user_id will be here after associations but I wanted them to be a composite primaryKey
*/
}
)
答案 0 :(得分:12)
事实上,我几乎从文档中得到了解决方案:
User = sequelize.define('user', {});
Project = sequelize.define('project', {});
UserProjects = sequelize.define('userProjects', {
status: DataTypes.STRING
});
User.belongsToMany(Project, { through: UserProjects });
Project.belongsToMany(User, { through: UserProjects });
默认情况下,上面的代码会将projectId和userId添加到UserProjects表中,并删除任何先前定义的主键属性 - 该表将由两个表的键组合唯一标识,并且没有理由有其他PK列。
答案 1 :(得分:2)
对于希望在进行迁移时根据联接表中的列(键)创建复合索引主键的任何人。您需要为希望充当表的组合主键的两列添加主键约束。
module.exports = {
up: function (queryInterface, Sequelize) {
return queryInterface.createTable('itemtags', {
itemId: {
type: Sequelize.INTEGER,
references: {
model: 'items',
key: 'id',
},
onDelete: 'CASCADE',
onUpdate: 'CASCADE',
allowNull: false
},
tagId: {
type: Sequelize.INTEGER,
references: {
model: 'tags',
key: 'id',
},
onDelete: 'CASCADE',
onUpdate: 'CASCADE',
allowNull: false
}
})
.then(() => {
return queryInterface.addConstraint('itemtags', ['itemId', 'tagId'], {
type: 'primary key',
name: 'gametag_pkey'
});
});
},
down: function (queryInterface, Sequelize) {
return queryInterface.dropTable('gametags');
}
};
与postgres中的ALTER TABLE ONLY my_table ADD CONSTRAINT pk_my_table PRIMARY KEY(column1,column2);
大致相同。