Question

我正在寻找专门用于python 3.7的功能。我在字符串中有一个数学表达式：

player1 = input("What is player 1's name ? ")
player2 = input("What is player 2's name ? ")

player1 = player1.title()
player2 = player2.title()
while True:
    print(player1 + " What do you choose ? rock / paper / scissors : ")
    a = input()

    print(player2 + " What do you choose ? rock / paper / scissors : ")
    b = input()
    if a == "rock" and b == "scissors" :
        print(player1, "won !!!")
    elif a == "scissors" and b == "rock":
        print(player2, "won !!!")

    elif a == "paper" and b == "rock":
        print(player1, "won !!!")
    elif a == "rock" and b == "paper":
        print(player2, "won !!!")

    elif a == "scissors" and b == "paper":
        print(player1, "won !!!")
    elif a == "paper" and b == "scissors":
        print(player2, "won !!!")

    elif a == b:
        print("Its a tie :-(")

    elif a or b != "rock" or "paper" or "scissors":

        print("Wrong input, Try again")
    end = input("Do you want to play again ? yes/no ") == "yes"
    if input == "yes":
        continue
    else:

        print('''

        GAME OVER''')
        break
#    elif input != "yes" or "no":
#        print("Wrong input, Try again. yes or no ?")

python 3.7中是否有任何内置函数可以对其进行评估？

PS：eval（）函数不起作用。

Answer 1

Python中电源操作的符号为**，而不是^。因此，请先更改您的字符串。

str_ ="2^10"

print(eval(str_.replace('^', '**')))  # -> 1024

请注意，eval是一个潜在的非常危险的功能。请勿盲目使用。

（非标准）模块numexpr是更安全的方法。

import numexpr

print(numexpr.evaluate(str_.replace('^', '**')))  # -> 1024

还要注意，不将"^"替换为"**"会导致8。发生这种情况是因为在Python中，^是binary XOR

在python 3.7中评估数学字符串

1 个答案: