Question

您好，我刚刚开始尝试教自己的python，并通过阅读的资源之一，看到了这个骰子游戏。所以我做了基本的练习，但是后来我想使其更加饱满。我的想法是添加一个循环，并在每个回合后提示用户在第一个q处输入，但现在输入0以尝试确定输入中是否有错误。

def gamestate():
   print('enter 0 if you would like to quit anything else to continue')
   game = input() 
   print(game == 0)  # diagnostic to check if value is correct 
   print(type(game))    #diagnostic to make sure type is correct
   print(game != str(0))


def play():
  print('do you want to play a game enter yes to start')
  game = '1'           #filler value
  game=input()
  str(game)
  if game == "yes":         #confirms start of the game
      Dice()
  else:
    print('Ok Goodbye')   #plays game anyways will fix after loop issue
  gamestate()
______________________________________________________________
  while  game !=str(0):    #cannot escape loop for some reason
      if game == str(0) :
          break      #to break 
      Dice()
      gamestate()
  print('ok good bye')    
  ___________________________________________________________
play()

首先，很抱歉，如果这段代码很长，但是我希望输入0作为中断循环的输入，那么我所得到的是必须杀死spyder中的控制台进程才能阻止其循环

Answer 1

您在2个不同的变量范围内有变量名游戏，因此它们具有不同的状态。尝试从gamestate（）返回游戏并比较该值 Short description of the scoping rules?

def gamestate():
   print('enter 0 if you would like to quit anything else to continue')
   game = input() 
   print(game == 0)  # diagnostic to check if value is correct 
   print(type(game))    #diagnostic to make sure type is correct
   print(game != str(0))
return game

  while  game !=str(0):    #cannot escape loop for some reason
      if gamestate() == str(0) :
          break      #to break 
      Dice()
  print('ok good bye')

Answer 2

您可以从gamestate函数返回game的值。

def gamestate():
   print('enter 0 if you would like to quit anything else to continue')
   game = input() 
   print(game == 0)  # diagnostic to check if value is correct 
   print(type(game))    #diagnostic to make sure type is correct
   print(game != str(0))
   return game

while  game !=str(0):
      Dice()
      game=gamestate()

您可以将game变量设置为全局变量

def gamestate():
   print('enter 0 if you would like to quit anything else to continue')
   global game
   game = input() 
   print(game == 0)  # diagnostic to check if value is correct 
   print(type(game))    #diagnostic to make sure type is correct
   print(game != str(0))
   return game


def play():
  print('do you want to play a game enter yes to start')
  global game
  game = '1'           #filler value
  game=input()
  str(game)
  if game == "yes":         #confirms start of the game
      Dice()
  else:
    print('Ok Goodbye')   #plays game anyways will fix after loop issue
  while  game !=str(0):    #cannot escape loop for some reason
      Dice()
      gamestate()
  print('ok good bye')    
play()

Answer 3

您必须从game函数返回gamestate值，并在while循环中分配它。检查以下代码：

def gamestate():
   print('enter 0 if you would like to quit anything else to continue')
   game = input() 
   print(game == 0)  # diagnostic to check if value is correct 
   print(type(game))    #diagnostic to make sure type is correct
   print(game != str(0))
   return game


def play():
  print('do you want to play a game enter yes to start')
  game = '1'           #filler value
  game=input()
  str(game)
  if game == "yes":         #confirms start of the game
    Dice()
  else:
    print('Ok Goodbye')   #plays game anyways will fix after loop issue
  gamestate()

  while  game !=str(0):    #cannot escape loop for some reason
      if game == str(0) :
          break      #to break 
      Dice()
      game = gamestate()
  print('ok good bye')   
play()

Answer 4

为了将零作为字符串进行比较，您只需要执行if game == "0":之类的操作即可。您可能遇到的问题是多余的空格字符，例如“ \ n”。如果您使用input().trimspace()，则将删除多余的字符，并与所需的值进行比较。

代码中的另一个问题是，如果游戏不等于“ 0”，它将进入while循环，因此将自动不满足后面的if条件。因此break从未被击中。

Answer 5

您需要修改程序以将输入转换为int而不是在多个位置将0转换为字符串。需要在while循环和gamestate函数中进行更改

为什么我不能杀死这个循环，为什么0不等于0？

5 个答案: