Question

我正在尝试从div获取姓名和联系电话。 div有时只有一个跨度，有时两个，有时三个。我的期望是：

我只需要姓名和联系电话
在某些情况下，姓名不可用，联系电话可用，然后应将姓名变量分配为“ N / A”
在某些情况下，联系人号码将不可用，姓名将可用，然后应将变量分配为“ N / A”

这是我到目前为止所拥有的：

// if you change url to url-1 and url-2 then you will see how it works.
url = "https://www.zillow.com/homedetails/19442-185th-Ave-SE-Renton-WA- 
98058/54831221_zpid/"
#url-1 = "https://www.zillow.com/homedetails/20713-61st-St-E-Bonney-Lake-WA-98391/99371104_zpid/"
#url-2 = "https://www.zillow.com/homes/fsbo/house_type/121319389_zpid/globalrelevanceex_sort/47.465758,-122.259207,47.404798,-122.398424_rect/12_zm/5f9305c92cX1-CRbri51bo8epha_yly1g_crid/0_mmm/"
browser = webdriver.Firefox()
browser.get(url)
time.sleep(5)

soup = bs4.BeautifulSoup(browser.page_source,'html.parser')

contacts = browser.find_elements_by_css_selector("span.listing-field")
contact_name = []
contact_phone = "N/A"
contact_web = "N/A"

for i in range(0, len(contacts)):
    if len(contacts[i].find_elements_by_tag_name("a")) > 0:
    contact_web = 
    contacts[i].find_element_by_tag_name("a").get_attribute("href")
    elif re.search("\\(\\d+\\)\\s+\\d+-\\d+", contacts[i].text):
        contact_phone = contacts[i].text
    else:
        contact_name.append(contacts[i].text)

print(contact_phone) // Output: (253) 335-8690
print(contact_name)  // Output: ['Sheetal Datta']

Answer 1

欢迎使用StackOverflow！您应该以编程方式（即根据条件）解决此问题。正如您已经提到的，

if the name exists and the contact number exists,
    use them
else if the name exists only,
    use the name and assign the contact number as 'N/A'
else if the contact number exists only,
    use the contact number and assign the name as 'N/A'

如您所见，您可以使用if-elif-else语句将上述伪代码实现为Python中的实际条件语句。根据网页的结构，在尝试从span读取值之前，您需要先检查public function getallRIS(){ $connect = $this->connect; /* THIS QUERY WORKS WITHOUT MULTIPLE IDS ON THE COLUMN $qx = "SELECT initiatives.location_id as init_location, initiatives.name as init_name, initiatives.startyear as init_startyear, initiatives.endyear as init_endyear, ST_AsText(locations.location) as locations_coord, locations.name as locations_name FROM locations JOIN initiatives on initiatives.location_id = locations.id"; */ $qx = "SELECT GROUP_CONCAT(initiatives.location_id SEPARATOR ',') as init_location, initiatives.name as init_name, initiatives.startyear as init_startyear, initiatives.endyear as init_endyear, ST_AsText(locations.location) as locations_coord, locations.name as locations_name FROM locations JOIN initiatives ON FIND_IN_SET(locations.id, initiatives.location_id) GROUP BY initiatives.location_id"; $queryx = "SELECT ST_AsText(ri_location) FROM ri;"; if($query = $connect->query($qx)){ }else{ echo $connect->error; } $count = $query->num_rows; $row = 1; while($fetch = $query->fetch_array(MYSQLI_ASSOC)){ $point = $fetch['locations_coord']; $point = str_replace(array("POINT(",")"),array("",""),$point); $point = str_replace(" ",",",$point); $coord = explode(",",$point); $lat = $coord[0]; $long = $coord[1]; echo' { lat: '.$lat.', lng: '.$long.', text: "'; echo ""; echo''.$fetch['init_name'].' Country: '.$fetch['locations_name'].' Info: '; echo"<a href=''>"; echo'View</a> Start Year: '.$fetch['init_startyear'].' End Year: '.$fetch['init_endyear'].'" }, '; $row++; } }是否存在，您可以按照此SO post进行操作。

Answer 2

您可以使用try: except:检查联系人姓名和电话号码是否存在，然后相应地分配值。查看代码...

from bs4 import BeautifulSoup
from selenium import webdriver
import time

url = ('https://www.zillow.com/homedetails/19442-185th-Ave-SE-Renton-WA-'
'98058/54831221_zpid/')

browser = webdriver.Firefox()
browser.get(url)
time.sleep(5)
soup = BeautifulSoup(browser.page_source,'html.parser')
browser.quit()
tag = soup.find('div',attrs={
    'class':'home-details-listing-provided-by zsg-content-section'})

try:
    contact_name = tag.find('span',attrs={
        'class':'listing-field'}).text
except:
    contact_name = 'N/A'

try:
    contact_phone = tag.find('span',attrs={
        'class':'listing-field'}).findNext('span').text
except:
    contact_phone = 'N/A'


print('Contact Name: {}\nContact Phone: {}'.format(
    contact_name,contact_phone))

输出：

Contact Name: Sheetal Datta
Contact Phone: (253) 335-8690

我如何只获得姓名和联系电话？

2 个答案: