我想从Android手机中检索所有联系人姓名和号码。然后,我想在ListView
中显示该数据。我怎样才能做到这一点?
答案 0 :(得分:0)
试试这个......
public void getContacts(ContentResolver cr) {
Cursor phones = cr.query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, null,
null, null);
while (phones.moveToNext()) {
String name = phones
.getString(phones
.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
String phoneNumber = phones
.getString(phones
.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
}
phones.close();// close cursor
}
通话方法
getContacts(this.getContentResolver());
答案 1 :(得分:0)
从这段代码中你将获得名称n号码保存在联系人列表中,将它们添加到arraylist或数组中,然后你可以在listview中显示它们
try {
String phoneNumber = null;
Uri CONTENT_URI = ContactsContract.Contacts.CONTENT_URI;
String _ID = ContactsContract.Contacts._ID;
String DISPLAY_NAME = ContactsContract.Contacts.DISPLAY_NAME;
String HAS_PHONE_NUMBER = ContactsContract.Contacts.HAS_PHONE_NUMBER;
Uri PhoneCONTENT_URI = ContactsContract.CommonDataKinds.Phone.CONTENT_URI;
String Phone_CONTACT_ID = ContactsContract.CommonDataKinds.Phone.CONTACT_ID;
String NUMBER = ContactsContract.CommonDataKinds.Phone.NUMBER;
ContentResolver contentResolver = getContentResolver();
Cursor cursor = contentResolver.query(CONTENT_URI, null, null,
null, null);
if (cursor.getCount() > 0) {
while (cursor.moveToNext()) {
String contact_id = cursor.getString(cursor
.getColumnIndex(_ID));
int hasPhoneNumber = Integer
.parseInt(cursor.getString(cursor
.getColumnIndex(HAS_PHONE_NUMBER)));
if (hasPhoneNumber > 0) {
Cursor phoneCursor = contentResolver.query(
PhoneCONTENT_URI, null, Phone_CONTACT_ID
+ " = ?", new String[] { contact_id },
null);
while (phoneCursor.moveToNext()) {
phoneNumber = phoneCursor.getString(phoneCursor
.getColumnIndex(NUMBER));
String contname = phoneCursor.getString(phoneCursor
.getColumnIndex(DISPLAY_NAME));
if (!contname.equals(null)) {
Toast.makeText(getApplicationContext(),
contname, Toast.LENGTH_SHORT).show();
}
}
}
phoneCursor.close();
}
}
}
} catch (Exception e) {
e.printStackTrace();
}