如何在Python中将DataFrame列值作为Neo4j Cypher查询值

Question

我是Neo4J的新手。我已经在本地主机上用螺栓连接了neo4j。我可以将neo4j查询转换为panda DataFrame，这是我的代码

from neo4j import GraphDatabase,basic_auth
import pandas as pd
url="bolt://localhost:7687"
driver=GraphDatabase.driver(url,auth=basic_auth("neo4j","admin"))
#graph.run("MATCH (a:Person) RETURN a.name, a.born LIMIT 3").to_table()

query="""MATCH (c :Customer {walletId:'01715578979'})-[:MR|:SENDS_MONEY]-(d)-[:PAYS]->(m)
WHERE NOT (c)-[]-(m)
RETURN m.name, COUNT(m.name) ORDER BY COUNT(m.name) DESC LIMIT 30"""

querywallet="""MATCH (c :Customer) RETURN c.walletId LIMIT 100"""

anotherquery="""MATCH (c :Customer {walletId:'01715578979'})-[:MR|:SENDS_MONEY]-(d)-[:PAYS]->(m)
WHERE NOT (c)-[]-(m)
RETURN c.walletId, m.walletId, m.name, COUNT(m.name) ORDER BY COUNT(m.name) DESC LIMIT 30"""




with driver.session()as graphdbsession:
    result=graphdbsession.run(querywallet)
    df=pd.DataFrame(result,columns=result.keys())


# =============================================================================
# with driver.session()as graphdbsessionwallet:
#     result=graphdbsessionwallet.run(anotherquery)
#     dfwall=pd.DataFrame(result,columns=result.keys())    
# =============================================================================

#this code is supposed to be return record for each element in my df Dataframe
for item in   df['c.walletId']:
    print(item)
    myquery="""MATCH (c :Customer {walletId:'item'})-[:MR|:SENDS_MONEY]-(d)-[:PAYS]->(m)
               WHERE NOT (c)-[]-(m)
               RETURN c.walletId, m.walletId, m.name, COUNT(m.name) ORDER BY COUNT(m.name) DESC LIMIT 30"""
    with driver.session() as graphdbsessionwallet:
        result=graphdbsessionwallet.run(myquery)
        bigdf=pd.DataFrame(result,columns=result.keys()) 

在这段代码中，我已将查询转换为DataFrame，对于DataFrame列元素，我试图从查询中获取重新记录，并将其制成汇总DataFrame。因此，我尝试遍历DataFrame元素（即“ ITEM”），并将该项目值作为查询语句 MATCH（c：Customer {walletId：'item'}）

但是我在这里得到空的DataFrame

有什么方法可以通过cypherquery赋予函数迭代值，也可以有任何好的解决方法。 请帮我解决这个问题。预先谢谢你