我正在描述Facebook的一小部分,这是Neo4j中的共同朋友计算与图形表示。我希望与所有初学者分享,并对图形数据库感兴趣,特别是我的小知识neo4j。
答案 0 :(得分:1)
计算两者之间相互朋友的Facebook表示示例:
Cypher Query代表朋友数据库:
CREATE (Keanu:Person {name:'Keanu Reeves', born:1964})
CREATE (Carrie:Person {name:'Carrie-Anne Moss', born:1967})
CREATE (Laurence:Person {name:'Laurence Fishburne', born:1961})
CREATE (JoelS:Person {name:'Joel Silver', born:1952})
CREATE (DemiM:Person {name:'Demi Moore', born:1962})
CREATE (KevinB:Person {name:'Kevin Bacon', born:1958})
CREATE (KieferS:Person {name:'Kiefer Sutherland', born:1966})
CREATE (NoahW:Person {name:'Noah Wyle', born:1971})
CREATE
(Keanu)-[:FRIENDS_WITH ]->(Carrie),
(Keanu)-[:FRIENDS_WITH ]->(Laurence),
(Keanu)-[:FRIENDS_WITH ]->(JoelS),
(Keanu)-[:FRIENDS_WITH ]->(DemiM),
(KevinB)-[:FRIENDS_WITH ]->(KieferS),
(KevinB)-[:FRIENDS_WITH ]->(NoahW),
(KevinB)-[:FRIENDS_WITH ]->(DemiM),
(KevinB)-[:FRIENDS_WITH ]->(JoelS);
等效图表示:
Cypher查询在KevinB和。之间检索共同朋友的名字 基努:
MATCH (Keanu:`Person` {name: "Keanu Reeves"})-[r]->(mutualFriend)<-[r1]-(Kevin:`Person` {name: "Kevin Bacon"}) RETURN mutualFriend.name
Cypher查询返回与其中一个相同数量的共同朋友 基努:
MATCH (Keanu:`Person` {name: "Keanu Reeves"})-[r]->(mutualFriend)<-[r1]-(unknown) RETURN COUNT (mutualFriend) as NumberOfMutualFriend,unknown.name