Flutter错误:类型'Future <dynamic>'不是类型'List <game>'的子类型

时间:2019-04-08 10:14:57

标签: firebase flutter google-cloud-firestore

我正在尝试使用不同的游戏列表构建一个应用程序。作为后端,我使用Firebase,并且连接正常,我对其进行了测试。无论如何,我在用Firebase的真实数据替换模拟数据时遇到问题。我总是会收到此错误:

  

“ Future ”类型不是“ List ”类型的子类型

我具有以下功能:

getGames() async{
 List newGamesList = [];

  QuerySnapshot result = awaitFirestore.instance.collection('products').getDocuments();
  List<DocumentSnapshot> documents = result.documents;
  documents.forEach((DocumentSnapshot doc) {
  Game game = new Game.fromDocument(doc);
  newGamesList.add(game);

});
}

“游戏”如下所示:

factory Game.fromDocument(DocumentSnapshot document) {

return new Game(
  name: document['name'],
  box: document['box'],
  cover: document['cover'],
  description: document['description'],

);
}

在我的构建小部件中,我将其称为“ getGames”:

new HorizontalGameController(getGames()),

您知道为什么会发生此错误以及如何解决该错误吗?

编辑:

为了更好地理解,这里是我的Horizo​​ntalGameController:

class HorizontalGameController extends StatelessWidget {
HorizontalGameController(this.gameItems);
final List<Game> gameItems;

@override
Widget build(BuildContext context) {
return new SizedBox.fromSize(
  size: const Size.fromHeight(240.0),
  child: new ListView.builder(
      itemCount: 1,
      scrollDirection: Axis.horizontal,
      padding: const EdgeInsets.only(left: 12.0, top: 4.0),
      itemBuilder: (BuildContext context, int position) {
        return GameContainerItem(context, gameItems[position]);
      }),
);
}
}

1 个答案:

答案 0 :(得分:1)

getGames没有返回您创建的gameList。使函数返回游戏列表。我无法测试,但请尝试一下

Future<List<Game>> getGames() async{
 List<Game> newGamesList = [];

  QuerySnapshot result = await Firestore.instance.collection('products').getDocuments();
  List<DocumentSnapshot> documents = result.documents;
  documents.forEach((DocumentSnapshot doc) {
  Game game = new Game.fromDocument(doc);
  newGamesList.add(game);

});

return newGamesList;
}

//then this
//new HorizontalGameController(await getGames()) //change this 

编辑    将new HorizontalGameController(await getGames())更改为以下代码(将它与futureBuilder打包在一起)。这将使小部件能够利用未来的价值。

FutureBuilder<List<Game>>(
                            future: getGames(),
                            builder: (context, AsyncSnapshot<List<Game>> gamelistSnapshot){
                                  return (gamelistSnapshot.hasData)? HorizontalGameController(gamelistSnapshot.data) : Container();
                            },
                        )