如何获得每天的总花费时间

Question

我在这里有一列，我需要获取每天的小时数（以后每1小时+1）

预期输出：

Date       | HourSpent
2017-12-08 | 6

我的代码尝试：

SELECT Cast(TransDateTime as Date), DateDIFF(hour,MIN(TransDateTime),MAX(TransDateTime)) as DateTime 
FROM GuestTransLedger where GuestExtID = '2016-120-5624873' 
GROUP BY Cast(TransDateTime as Date) ORDER BY 1 DESC

Answer 1

尝试一下：

select convert(date, datetime_column) as Date, count(distinct datepart(hour,datetime_column)) as HourSpent
from tbl
group by convert(date, datetime_column)

Answer 2

在这里日历表方法可能是一个不错的选择：

WITH cte AS (
    SELECT '2017-12-08 00:00:00' AS dt UNION ALL
    SELECT '2017-12-08 01:00:00' UNION ALL
    SELECT '2017-12-08 02:00:00' UNION ALL
    ...
    SELECT '2017-12-08 22:00:00' UNION ALL
    SELECT '2017-12-08 23:00:00'
)

SELECT
    CONVERT(date, t1.dt) AS Date,
    COUNT(DISTINCT t1.dt) AS HoursSpent
FROM cte t1
INNER JOIN yourTable t2
    ON t2.DateTime >= t1.dt AND t2.DateTime < DATEADD(HOUR, 1, t1.dt)
GROUP BY
    CONVERT(date, t1.dt);

此答案唯一棘手的部分是生成小时日历表。 See here是在SQL Server中执行此操作的一种方法。