Question

我试图在一张表中获得2列的总和，但条件不同，唯一的区别是每个部门的金额是根据17％的保证金计算的。结果应为按事件名称和事件ID分组的总收入。

对于sql报表，我编写了2条具有不同条件的sql语句，并为2列获取了正确的值，但是分别地，我以某种方式对两者进行了求和，但这只是针对一个事件。

SELECT EVT_ID, Event_Desc, Sum(Order_Total) as Total + (Select SUm(Order_Total *0.17) as Total from Orders Join Events EM On OrD.EVT_ID = EV.EVENTS_ID 
where EVT_START_DATE between '2019-01-01' and '2019-01-31' Order_Department = 'FAB'  )
From Orders Join Events EM On OrD.EVT_ID = EV.EVENTS_ID 
where EVT_START_DATE between '2019-01-01' and '2019-01-31' Order_Department <> 'FAB'  
Group by EVT_ID, Event_Desc

Answer 1

select EVT_ID, Event_Desc, sum(Total)as Total 
from 
(
SELECT EVT_ID, Event_Desc, Sum(Order_Total) as Total 
 From Orders 
 Join Events EM On OrD.EVT_ID = EV.EVENTS_ID 
 where EVT_START_DATE between '2019-01-01' and '2019-01-31' and Order_Department <> 'FAB'
Group by EVT_ID, Event_Desc 
 union
Select EVT_ID, Event_Desc, SUm(Order_Total *0.17) as Total 
from Orders 
Join Events EM On OrD.EVT_ID = EV.EVENTS_ID 
 where EVT_START_DATE between '2019-01-01' and '2019-01-31' and Order_Department = 'FAB' )  tbl   
 Group by EVT_ID, Event_Desc

OR

 SELECT EVT_ID, Event_Desc, Sum(case when Order_Department = 'FAB' then Order_Total else Order_Total *0.17 end ) as Total 
 From Orders 
 Join Events EM On OrD.EVT_ID = EV.EVENTS_ID 
 where EVT_START_DATE between '2019-01-01' and '2019-01-31'  
Group by EVT_ID, Event_Desc

Answer 2

如果我正确地跟随了您，则可以使用条件汇总来解决此问题。您可以在CASE聚合函数中使用SUM构造来检查当前记录属于哪个部门并进行相应的计算。

SELECT
    o.evt_id,
    event_desc,
    SUM(CASE 
        WHEN order_department = 'FAB' THEN order_total * 0.17 
        ELSE order_total END
    ) AS Total
FROM orders o
INNER JOIN events e On o.evt_id = e.events_id    
WHERE evt_start_date BETWEEN '2019-01-01' and '2019-01-31'
GROUP BY 
    o.evt_id,
    event_desc

NB：查询中的大多数列都没有前缀表别名，因此不清楚它们来自哪个表。当可以从您的sql代码中进行有根据的猜测时，我添加了它们，并且我建议您为所有其余的代码添加前缀。

总数为2的sql中的select语句，其中where子句

2 个答案: