我希望结合2选择与不同的where子句 首先选择是
push
结果是:
SELECT name,
COUNT(telat_1_30min)
FROM kkpsurabaya
WHERE telat_1_30min >= 1
AND telat_1_30min <= 30;
和其他选择是
name | telat1 1-30 min
FERI WAHYUDI | 2
结果是:
SELECT COUNT(late) AS 'telat 31-60min'
FROM kkpsurabaya
WHERE timetable NOT LIKE 'minggu'
AND timetable NOT LIKE 'sabtu'
AND late <= 90
AND late >= 61;
我想要像
那样结合name | telat1 31-60 min
KARIYONO | 1
我尝试使用查询
name | telat1 1-30 min|telat1 31-60 min
FERI WAHYUDI | 2 |0
KARIYONO | 0 |1
结果是:
SELECT name,
'telat < 30menit' = (SELECT
COUNT(telat_1_30min) AS 'telat 1-30min'
FROM kkpsurabaya
WHERE telat_1_30min >= 1
AND telat_1_30min <= 30),
'telat 31-60 min' = (SELECT
COUNT(late) AS telat_60_90
FROM kkpsurabaya
WHERE timetable NOT LIKE 'minggu'
AND timetable NOT LIKE 'sabtu'
AND late <= 90
AND late >= 61)
FROM kkpsurabaya
GROUP BY Name;
telat_1_30min类型数据为int
晚期类型数据是int
解决
name | telat1 1-30 min|telat1 31-60 min
FERI WAHYUDI | 2 |1
KARIYONO | 2 |1
答案 0 :(得分:2)
[UIUtils registerLocalNotification:describe:completed:]
修改
select name, count( telat_1_30min) as ' telat1 1-30 min',0 as 'telat1 31-60 min'
from kkpsurabaya where telat_1_30min >=1 and telat_1_30min <=30
union all
SELECT name,0 as ' telat1 1-30 min', count(late) as 'telat 31-60min'
FROM kkpsurabaya WHERE timetable not like 'minggu' and timetable not like 'sabtu' and late <=90 and late >=61