Question

表格

api_channel

 channel_id| channel_company
-----------+-------------
    1      |     copmany1     
    2      |     copmany2  
    3      |     copmany3 
    4      |     copmany4
    5      |     copmany5  
-----------+-------------

充值

 id|amount|  status| channel_id
---+------+--------+------------
 1 | 248  | success|    2
 2 | 240  | failed |    1
 3 | 495  | failed |    1
 4 | 150  | success|    2
 5 | 278  | failed |    3
---+------+--------+-------------

想要的结果：

 id|channel_company|success_total| failed_total | pending_total
---+---------------+-------------+--------------+--------------
 1 |    copmany1   |    0        |    735       |       0
 2 |    copmany2   |   398       |     0        |       0
 3 |    copmany3   |    0        |    278       |       0
 4 |    copmany4   |    0        |     0        |       0
 5 |    copmany5   |    0        |     0        |       0
---+---------------+-------------+--------------+--------------

我的查询

SELECT 
  SUM(R.recharge_amount) AS total, A.channel_id, A.channel_company, 
  R.api_channel, R.status, R.recharge_amount, R.created_at 
FROM api_channels A LEFT JOIN recharges R 
  ON R.api_channel = A.channel_id 
WHERE R.status ='Success' OR R.status ='Failed' OR R.status ='Pending' 
  AND CAST(R.created_at AS DATE)= CURRENT_DATE GROUP BY R.status

有三种状态，成功，失败，待处理，但是有时这些值变为空，例如充值表会看到没有待处理的充值。

Answer 1

加入2个表并应用条件聚合：

select
  a.channel_id,
  a.channel_company,
  sum(case when r.status = 'success' then r.amount else 0 end) success_total,
  sum(case when r.status = 'failed' then r.amount else 0 end) failed_total,
  sum(case when r.status = 'pending' then r.amount else 0 end) pending_total
from api_channel a left join recharges r
on a.channel_id = r.channel_id
group by 
  a.channel_id,
  a.channel_company

Answer 2

一种方法是条件聚合，即使用CASE表达式作为sum()的参数，如果状态是您要计数的状态，则仅产生数量，否则使用0。对于没有coalesce()且处于通缉状态的公司，请使用0的默认值recharges。

SELECT ac.channel_id id,
       ac.channel_company,
       coalesce(sum(CASE
                      WHEN r.status = 'success' THEN
                        r.amount
                      ELSE
                        0
                    END), 0) success_total,
       coalesce(sum(CASE
                      WHEN r.status = 'failed' THEN
                        r.amount
                      ELSE
                        0
                    END), 0) failed_total,
       coalesce(sum(CASE
                      WHEN r.status = 'pending' THEN
                        r.amount
                      ELSE
                        0
                    END), 0) pending_total
       FROM api_channel ac
            LEFT JOIN recharges r
                      ON r.channel_id = ac.channel_id
       GROUP BY ac.channel_id,
                ac.channel_company;

我如何获得每一列的总和

2 个答案: