Question

CREATE TEMPORARY TABLE

CREATE TEMP TABLE total(
gid SERIAL,
zoom smallint NOT NULL,
point integer NOT NULL,
size integer NOT NULL
);

插入数据

INSERT INTO total(zoom, point, size) VALUES(9,51,21);
INSERT INTO total(zoom, point, size) VALUES(9,75,45);
INSERT INTO total(zoom, point, size) VALUES(9,74,34);
INSERT INTO total(zoom, point, size) VALUES(10,75,4);
INSERT INTO total(zoom, point, size) VALUES(10,72,63);
INSERT INTO total(zoom, point, size) VALUES(10,85,22);

计算点数，根据ZOOM增加尺寸

SELECT zoom,
       count(*) AS point,
       SUM(size) AS size
FROM total
GROUP BY zoom
ORDER BY zoom;

结果：

 zoom | point | size 
------+-------+------
    9 |     3 |  100
   10 |     3 |   89
(2 rows)

问题

如何返回每列的总数？

通缉结果：

 zoom | point | size 
------+-------+------
    9 |     3 |  100
   10 |     3 |   89
------+-------+------        
Total |     6 |  189

Answer 1

模拟汇总的方法是简单地运行第二个执行汇总的查询。但是，列中的所有值必须具有相同的数据类型。如果要显示标签result.isSuccess()，则需要将基本查询中的数字'Total'转换为文本：

但是，由于您希望按实际缩放值排序，您还需要在结果中保留整数值。

zoom是必要的，以确保联盟第一部分的行实际上保持“在顶部”

sort_order

返回：

select zoom, point, size
FROM (
  SELECT zoom::text as zoom,
         zoom as zoom_value,
         count(*) AS point,
         SUM(size) AS size, 
         1 as sort_order
  FROM total
  GROUP BY zoom
  UNION ALL
  SELECT 'Total', 
         null,
         count(*) AS point,
         SUM(size) AS size, 
         2 as sort_order
  FROM total
) t
order by sort_order, zoom_value;

使用最新的Postgres版本，您可以执行以下操作：

zoom  | point | size
------+-------+-----
9     |     3 |  100
10    |     3 |   89
Total |     6 |  189

Answer 2

SELECT
zoom,
SUM(point) AS point,
SUM(size) AS size
FROM
(
SELECT zoom,
       count(*) AS point,
       SUM(size) AS size
FROM total
GROUP BY zoom
) x
ORDER BY zoom

如何获得每列的总和？

2 个答案: