Question

我在自定义无状态视图中有一个var viewer = new Cesium.Viewer ('cesiumContainer', { scene3DOnly: false, selectionIndication: false, baseLayerPicker: true }); Cesium.Ion.defaultAccessToken = 'eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJqdGkiOiI4ODY0ZjkwMy03YmZlLTRlNGEtYmNhOS0xMDBlZGVmNDRkZGMiLCJpZCI6OTE4MSwic2NvcGVzIjpbImFzciIsImdjIl0sImlhdCI6MTU1MzYxMjM5Mn0.aYYX1f1MQfg9zLFu0vnP3A56Neo4Y_N3G2O5tuTS0XM'; // Enable lighting based on sun/moon positions viewer.scene.globe.enableLighting = true; //Stazione di terra var entity = viewer.entities.add({ position: Cesium.Cartesian3.fromDegrees(12.04, 44.23), ellipse : { semiMinorAxis : 150000.0, semiMajorAxis : 150000.0, material : Cesium.Color.YELLOW.withAlpha(0.5) } }); var ellipse = entity.ellipse; ellipse.material = new Cesium.GridMaterialProperty({ color : Cesium.Color.YELLOW, cellAlpha : 0.2, lineCount : new Cesium.Cartesian2(8, 8), lineThickness : new Cesium.Cartesian2(2.0, 2.0) }); var GroundStation = viewer.entities.add({ name : 'Ground Station', position : Cesium.Cartesian3.fromDegrees(12.07, 44.23), point : { pixelSize : 5, color : Cesium.Color.RED, outlineColor : Cesium.Color.WHITE, outlineWidth : 2 }, label : { text : 'Ground Station', font : '14pt monospace', style: Cesium.LabelStyle.FILL_AND_OUTLINE, outlineWidth : 2, verticalOrigin : Cesium.VerticalOrigin.BOTTOM, pixelOffset : new Cesium.Cartesian2(0, -9) } });。当GestureDetector触发时，我显示一个显示一些信息的小吃店。当用户快速单击多次时，它将永远显示小吃店。

source code

onTap

我想禁用GestureDetector( onTap: () { Clipboard.setData(new ClipboardData(text: idText)); Scaffold.of(context).showSnackBar(SnackBar (content: Text('ID copied'))); }, child: Icon(Icons.content_copy,), }几秒钟，然后才能再次单击它。

Answer 1

将其包装在AbsorbPointer

中

var shouldAbsorb = true;

AbsorbPointer(
    absorbing: shouldAbsorb,
    child: GestureDetector(
      onTap: () {
        Navigator.of(context).pop();
      },
      child: Container(
        color: Colors.red,
      ),
    ),
  )

Answer 2

您可以使用

bool _condition = true;
//...

GestureDetector(
  onTap: _condition
      ? () {
          // making it false when onTap() is pressed and after 1 second we'll make it true
          setState(() => _condition = false);
          Timer(Duration(seconds: 1), () => setState(() => _condition = true));

          // your implementation
          Clipboard.setData(new ClipboardData(text: idText));
          Scaffold.of(context).showSnackBar(SnackBar
              (content: Text('ID copied')));
        }
      : null, // disable onTap if condition is false
  child: Icon(Icons.content_copy,),
),

Answer 3

我个人使用GestureDetector中的其他两种方法：

onTapDown：当用户按下您的窗口小部件时。

onTapUp：当用户离开窗口小部件时。

onTap：是在点击并随后点击时显示的。如果用户将手指滑动太多，则Flutter会像取消水龙头一样。

onTapCancel：用户取消时。

bool pressing = false;

GestureDetector(
  // when user is pressing
  onTapDown: (details) {
    setState(() {
      pressing = true;
    });
  },
  // when user leaved
  onTapUp: (details) {
    setState(() {
      pressing = false;
    });
  },
  // when user leaved
  onTapCancel: () {
    setState(() {
      pressing = false;
    });
  }
  // the action to do when user tap
  onTap: () {
    // code...
  }
);

以下是文档：Flutter GestureDetector Documentation

Flutter：如何在手势检测器中暂时禁用onTap？

3 个答案: