将一个数组(1)附加到另一个数组(2) Update array(2)会同时更新
我将发布的脚本将显示2个不同的结果 函数-def Report_Results_Fail():-失败 函数-def Report_Results_Ok():-可以
我试图理解为什么第一次失败
def Processes_Last_Runs_Blanks_Clear(v_User_List):
v_Blanks_Clear = [] ; v_Blanks_Clear.append("--||--")
for i in range(len(v_User_List)):
v_This = "-"#+" " * v_User_Len
#v_This = v_This[0:v_User_Len]
v_Blanks_Clear.append(v_This)
return v_Blanks_Clear
def Active_User_List():
# Read from file so array looks like this
v_Users_Active = []
v_Users_Active.append("Jeff")
v_Users_Active.append("Kenny")
v_Users_Active.append("Lenny")
v_Users_Active.append("Manny")
v_Users_Active.append("Nanny")
return v_Users_Active
def Report_Results_Fail():
v_Users_Active = Active_User_List()
v_Blanks = Processes_Last_Runs_Blanks_Clear(v_Users_Active)
v_Report = []
v_Report.append(v_Blanks)
v_Report[0][0] = "Process"
v_Report[0][1] = "Users"
for i in range(5):
if i == len(v_Report):
v_Report.append(v_Blanks)
v_Report[i][1] = str(i)
for i in range(len(v_Report)):
print i,v_Report[i]
def Report_Results_Ok():
v_Users_Active = Active_User_List()
v_Report = []
v_Report.append(Processes_Last_Runs_Blanks_Clear(v_Users_Active))
v_Report[0][0] = "Process"
v_Report[0][1] = "Users"
for i in range(5):
if i == len(v_Report):
v_Report.append(Processes_Last_Runs_Blanks_Clear(v_Users_Active))
v_Report[i][1] = str(i)
for i in range(len(v_Report)):
print i,v_Report[i]
print "Running on Imac High Sierra 10.13.6 - Python Version 2.7.10"
print "Report_Results_Fail()"
Report_Results_Fail()
print "Report_Results_Ok()"
Report_Results_Ok()
在Imac High Sierra 10.13.6上运行-Python版本2.7.10
Report_Results_Fail()
0 ['Process','4','-','-','-','-']
1 ['Process','4','-','-','-','-']
2 ['Process','4','-','-','-','-']
3 ['Process','4','-','-','-','-']
4 ['Process','4','-','-','-','-']
Report_Results_Ok()
0 ['Process','0','-','-','-','-']
1 ['-||-','1','-','-','-','-']
2 ['-||-','2','-','-','-','-']
3 ['-||-','3','-','-','-','-']
4 ['-||-','4','-','-','-','-']