Question

设计一个应用程序，该应用程序会从1到100的随机数中进行选择，然后提示用户猜测该数字，并警告用户只有5次尝试才能正确猜测。每次猜测之后，向用户报告他或她是正确的还是猜测过高或过低。如果猜对了，则打印出祝贺消息。如果猜错5次失败，请打印一条消息，说明游戏已结束。在游戏结束时，提示用户指示他/她是否希望再次玩游戏。

我特别需要结尾的帮助，我想代码的布局也要...我运行它并且它不断运行，我尝试使用了多个网站和我的教科书，但是没有运气，在此先谢谢您！！

Java，Net bean 8.2

<p-card>
  <p-header>
    <div style="float: left;">
      <i class="pi pi-pencil" style="font-size: 1.5em" (click)="edit()" style="cursor: pointer; margin-left: 8px;"></i>
      <i class="pi pi-trash" style="font-size: 1.5em" (click)="delete()" style="cursor: pointer; margin-left: 8px;"></i>
    </div>
    <div style="float: right;">
      <p style="margin-right: 8px; font-size: 10px;">Posted by {{username}} <i class="pi pi-star" style="font-size: 1.0em"></i>{{points}} points</p>
    </div>
  </p-header>
  <div class="chart-container" style="position: relative; width: 325px !important;">
    <canvas id="{{pollKey}}"></canvas>
    <div class="checkbox-container" style="position: absolute; top: 32px; left: 300px;">
      <input *ngFor="let choice of inputChoices" class="checkbox" type="checkbox" (click)="vote(choice.id)" id="{{choice.id}}" style="display: block; cursor: pointer;">
    </div>
  </div>
  <p-footer>
    <div style="text-align: left;
    background-color: rgba(19, 32, 98, 0.7);
    width: fit-content;
    padding: 5px;
    color: white;
    border-radius: 20px;
    font-size: 8px;
    font-weight: 600;">
      {{getScoringType()}}
    </div>
  </p-footer>
</p-card>

}

输入您的猜测（0退出）：20 你的猜测太低了

输入您的猜测（0退出）：35 你的猜测太低了

输入您的猜测（0退出）：80 你的猜测太高了

输入您的猜测（0退出）：74 你的猜测太高了

输入您的猜测（0退出）：56 对！猜猜：5

再次播放（y / n）？

Answer 1

评论对：

您需要处理代码格式。这使它更具可读性。
您的生成器生成的值介于1到101之间。它应该只是answer = generator.nextInt(100)+1;
您的循环和某些逻辑错误
我建议始终在public static void main外部创建一个单独的方法。这是常见的做法，这也使您可以再次调用自身的方法。

这就是我要解决的方法：

import java.util.Random; import java.util.Scanner;

class Main {
  public static Scanner scan = new Scanner(System.in);

  public static void main (String[]args) {
    runGame();
  }

  public static void runGame() {
    String another = "";
    int answer, guess,attemptsNum = 0;
    final int maxAttempts = 5;

    Random generator = new Random();
    answer = generator.nextInt(100)+1;

    System.out.println("Guess a number between 1 and 100");
    System.out.println("Enter your guess (0 to quit):");

    guess = scan.nextInt();
    while (guess != answer && attemptsNum < maxAttempts-1 && guess != 0 ) {
      if(guess==answer)
            System.out.println("Right!");
      else if (guess<answer) {
        System.out.println("Your guess was too LOW.");
        attemptsNum++;
        guess = scan.nextInt();
      } 
      else {
        System.out.println("Your guess was too HIGH.");
        attemptsNum++;
        guess = scan.nextInt();
      }
    }

    System.out.println ("The number was " + answer);
    System.out.println("Want to Play again?(y/n)");
    another = scan.next();
    System.out.println("another = " + another);
    if(another.equals("y")) {
      runGame();
    } else {
      System.out.println("Goodbye!");
    }
  }
}

但是无论哪种方式，只要继续练习即可。您会掌握的！

Answer 2

我看到外部的while循环需要重新构造，并且某些逻辑放错了位置。试用修订版，希望对您有所帮助。如果您有任何问题，请评论我。

import java.util.Random;
import java.util.Scanner;

public class GuessingGame {

    public static void main(String[] args) {

        int answer, guess, attemptsNum = 0;
        final int maxAttempts = 5;
        String str, another = "y";

        Scanner scan = new Scanner(System.in);
        Random generator = new Random();
        answer = generator.nextInt(101) + 1;

        while (another.equals("y") || another.equals("Y")) {
            System.out.println("Guess a number between 1 and 100");

            System.out.println("Enter your guess (0 to quit):");

            guess = scan.nextInt();
            attemptsNum = 0;
            while (guess != 0)

            {
                attemptsNum++;
                if (guess == answer) {
                    System.out.println("Right!");
                    break;
                } else if (guess < answer)
                    System.out.println("Your guess was too LOW.");
                else if (guess > answer)
                    System.out.println("Your guess was too HIGH.");

                if (attemptsNum == maxAttempts) {
                    System.out.println("The number was " + answer);
                    break;

                }

                System.out.println("Enter your guess (0 to quit):");
                guess = scan.nextInt();
            }

            System.out.println("Want to Play again?(y/n)");
            another = scan.next();
        }
        System.out.println("Thanks for playing");
    }
}

Answer 3

我可以看到javapedia.net首先回答了这个问题，但是我独立提出了这个答案。我添加了括号以提高可读性。 letsNum ++被添加到if语句中，以使猜测值过高或过低。

import java.util.Random;
import java.util.Scanner;

public class GuessingGame {

    public static void main(String[] args) {

        int answer, guess, attemptsNum = 0;
        final int maxAttempts = 5;
        String str, another = "y";

        Scanner scan = new Scanner(System.in);
        Random generator = new Random();
        answer = generator.nextInt(101) + 1;

        System.out.println("Guess a number between 1 and 100");
        System.out.println("Enter your guess (0 to quit):");

        guess = scan.nextInt();
        while (guess != 0) {
            if (guess == answer) {
                System.out.println("Right!");
                guess = 0;
            } else if (guess < answer) {
                System.out.println("Your guess was too LOW.");
                attemptsNum++;
                guess = scan.nextInt();
            } else {
                System.out.println("Your guess was too HIGH.");
                attemptsNum++;
                guess = scan.nextInt();
            }
            if (attemptsNum >= (maxAttempts-1)) {
                System.out.println("The number was " + answer);
            }
        }
    }
}

猜游戏-随机＃1至100，要求用户5次猜正确的数字.....初学者JAVA

3 个答案: