Question

在此程序中，用户必须考虑一个数字，然后由计算机进行猜测。

计算机将向用户询问范围，
计算机将猜测边界之间的数字，
用户将键入“较高”或“较低”以使计算机猜测正确的数字，
如果计算机猜对了答案，则用户将输入“是”，并打印正确的声明。

下面的代码是我正在处理的代码，但是，我陷入了一些问题。请帮帮我！谢谢！

我发现的问题：

1。。我不了解如何在类内部但在主函数外部定义randomInt函数。

2。。我尝试了该程序，但是计算机的猜测很奇怪。计算机不会根据我的指南猜测一个数字。

public class Guess
{

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        Random rand = new Random();

        //ask about the lower bound,
        TextIO.putln("Hey there! Welcom to the game!\n"
                + "I'm going to guess a number, and you have to pick it\n"
                + "and you get to decide the bounds.\n" +
                "What should the lower bound be?");
        int lowerlimit = TextIO.getInt();

        //if the user enter the number lower than 0,
        while ((lowerlimit < 0))
        {
            TextIO.putln("ERROR Please enter a number that greater than 0");
            lowerlimit = TextIO.getInt();
        }

        //ask about the upper bound,
        TextIO.putln("Great! How about the upper bound?");
        int upperlimit = TextIO.getInt();

        //if the user enter the number lower than 0,
        while ((upperlimit <= lowerlimit))
        {
            TextIO.putln("ERROR Please enter a number "
                    + "that greater than the lower bound.");
            upperlimit = TextIO.getInt();
        }

        //Print the range and instruction,  
        TextIO.putln("Ok. In the range between " + lowerlimit +
                " and " + upperlimit + ":" + "\nPlease enter 'lower'/'higher' "
                + "when the number I picked is not correct\n"
                + "Enter 'yes' when I picked the right number"
        );

        //Generate the random number between the range,
        int randNum = (int) ((Math.random() * ((upperlimit - lowerlimit) + 1)) + lowerlimit);
        String feedback = "";


        while (!feedback.equals("yes"))
        {
            TextIO.putln("I think it is " + randNum);
            feedback = in.nextLine();

            //When the computer need to pick a lower number, 
            if (feedback.equals("lower"))
            {
                upperlimit = randNum - 1;
                randNum = (int) ((Math.random() * ((upperlimit - lowerlimit) + 1)) + lowerlimit);

            }

            //When the computer need to pick a higher number, 
            else if (feedback.equals("higher"))
            {
                lowerlimit = randNum + 1;
                randNum = (int) ((Math.random() * ((upperlimit - lowerlimit) + 1)) + lowerlimit);

            }
        }
        {
            //When the user guesses the correct number,
            TextIO.putln("Yes! Correct!:)");
        }
        in.close();
    }

    public static int randomInt(int min, int max) {
        return (int) ((Math.random() * ((max - min) + 1)) + min);
    }
} // end of Guess class

Answer 1

我阅读了您的代码，但做了些改动。我认为我的更改将反映出您可以做的更好的事情，但是请注意以下几点：

您必须使用SecureRandom类，这要好得多。您必须使用nextInt来获取随机数，而我只能创建该类型的一个对象
您可以在一段时间内计算随机数，直到获得真实结果为止。
您必须使用in.next()，因为在读取字符串之前会忽略空格。如果您使用nextLine()，则nextInt()仅读取数字，而nextLine()首先将捕获零个字符串。

它是改进的代码：

public class Guess
{
    public static SecureRandom random = new SecureRandom();
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);

        //ask about the lower bound
        System.out.println("Hey there! Welcome to the game!\n"
                + "I'm going to guess a number, and you have to pick it\n"
                + "and you get to decide the bounds.\n" +
                "What should the lower bound be?");
        int lower = in.nextInt();

        //if the user enter the number lower than 0
        while (lower < 0)
        {
            System.out.println("ERROR Please enter a number that greater than 0");
            lower = in.nextInt();
        }

        //ask about the upper bound
        System.out.println("Great! How about the upper bound?");
        int upper = in.nextInt();

        //if the user enter the number lower than 0
        while (upper <= lower)
        {
            System.out.println("ERROR Please enter a number "
                    + "that greater than the lower bound.");
            upper = in.nextInt();
        }

        //Print the range and instruction
        System.out.println("Ok. In the range between " + lower +
                " and " + upper + ":" + "\nPlease enter 'lower'/'higher' "
                + "when the number I picked is not correct\n"
                + "Enter 'yes' when I picked the right number"
        );

        //Generate the random number between the range
        String feedback = "";

        while (!feedback.equals("yes"))
        {
            int randNum = lower + random.nextInt(upper - lower + 1);
            System.out.println("I think it is " + randNum);
            feedback = in.next();

            //When the computer need to pick a lower number,
            if (feedback.equals("lower"))
                upper = randNum - 1;

            // When the computer need to pick a higher number,
            if (feedback.equals("upper"))
                lower = randNum + 1;
        }
        //When the user guesses the correct number,
        System.out.println("Yes! Correct!");
        in.close();
    }
}

希望对您有帮助。

随机数游戏问题（用户选择号码，要猜测的计算机）

1 个答案: